Answer:
1.85
Step-by-step explanation:
20.2-18.35=1.85
1 mile = 1760 yards
20 * 1.151 = 23.02
23.02 * 1760 = 40,515.2
40,515.2 / 60 = 675.243~
675.243~ / 60 = 11.2542~
They are traveling 11.25 yards per second
I took the number of knots multiplied by the approximate miles per hour equal
Then multiplied that by the number of yards in a mile, and then divided that by the number of minutes in an hour, and divided that by the number of seconds in a minute. That is how I got the answer, I hope it helps!
Answer:
well if jenny put 6 MORE marshmellows in her cup thenjulie and they added up to 6 then julie must of not had any
Step-by-step explanation:
Answer: He rode 4.8 miles each day.
Variable: x = Constant distance distance traveledd each day.
Equation : 10+5x=34
Step-by-step explanation:
Total distance needs to travel = 34 miles
Distance already traveled = 10 miles
He will ride bicycle for 5 more days.
Let x = Constant distance distance traveledd each day.
Total distance = 10+5x
i.e.

Hence, he rode 4.8 miles each day.
Answer:
Fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.
Step-by-step explanation:
Given the figure with dimensions. we have to find the area of given figure.
Area of figure=ar(1)+ar(2)+ar(3)
Area of region 1 = ar(ANGI)+ar(AIB)
![=L\times B+\frac{1}{2}\times base\times height\\\\=[1500\times (5000-2000-1500)]+\frac{1}{2}\times (3000-1500)\times (5000-2000-1500)\\\\=3375000m^2=337.5ha](https://tex.z-dn.net/?f=%3DL%5Ctimes%20B%2B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20base%5Ctimes%20height%5C%5C%5C%5C%3D%5B1500%5Ctimes%20%285000-2000-1500%29%5D%2B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%283000-1500%29%5Ctimes%20%285000-2000-1500%29%5C%5C%5C%5C%3D3375000m%5E2%3D337.5ha)
Area of region 2 = ar(DHBC)

Area of region 3 = ar(GFEH)

Hence, Area of figure=ar(1)+ar(2)+ar(3)=337.5ha+300ha+350ha
=987.5 ha
Now, we have to do straight-line fencing such that area become half and cost of fencing is minimum.
Let the fencing be done through x m downward from B which divides the two into equal area.
⇒ Area of upper part above fencing=Area of lower part below fencing
⇒
Hence, fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.