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Luda [366]
4 years ago
10

Which of the following represents 5 x to the 4 ninths power in radical form? ninth root of 5 x to the fourth power fourth root o

f 5 x to the ninth power 5 ninth root of x to the fourth power 5 fourth root of x to the ninth power
Mathematics
2 answers:
JulijaS [17]4 years ago
8 0
It would be helpful to write the statement above as an algebraic expression. We do it as follows:

<span>5 x to the 4 ninths power  = (5x)^4/9

In radical form, it should be written as:

ninth root of 5x to the fourth

Therefore, the correct answer is the first option.</span>
Paladinen [302]4 years ago
4 0

Answer:

 

5 ninth root of x to the fourth power

Step-by-step explanation:

 

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A board that is 4 1/2 feet long weighs 7 1/5 pounds. How much would one foot of the board
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Answer:

A board that is 4 1/2 feet long weighs 7 1/5 pounds. How much would one foot of the board weigh? Write your answer as a mixed number

Step-by-step explanation:

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3 years ago
If sin θ = cos 40°, 0&lt;θ&lt;90°, what is θ?
Bezzdna [24]

Answer:

θ =  50 degrees

Step-by-step explanation:

we have  sin θ = cos 40°

 θ = arcsin ( cos 40°)

and make sure θ is less than 90  and greater than 0

 θ = arcsin (0.766044443)

θ =  50 degrees

3 0
3 years ago
What is the probability of drawing the compliment of a king or a
inna [77]

Answer:

The probability of drawing the compliment of a king or a  queen from a standard deck of playing cards = 0.846

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Let 'S' be the sample space associated with the drawing of a card

n (S) = 52C₁ = 52

Let E₁ be the event of the card drawn being a king

n( E_{1} ) = 4 _{C_{1} }  = 4

Let E₂ be the event of the card drawn being a queen

n( E_{2} ) = 4 _{C_{1} }  = 4

But E₁ and E₂ are mutually exclusive events

since E₁ U E₂ is the event of drawing a king or a queen

<u><em>step(ii):-</em></u>

The probability  of drawing of a king or a  queen from a standard deck of playing cards

P( E₁ U E₂ ) = P(E₁) +P(E₂)

                 = \frac{4}{52} + \frac{4}{52}

P( E₁ U E₂ ) = \frac{8}{52}

<u><em>step(iii):-</em></u>

The probability of drawing the compliment of a king or a  queen from a standard deck of playing cards

P(E_{1}UE_{2})  ^{-} = 1- P(E_{1} U E_{2} )

P(E_{1}UE_{2})  ^{-} = 1- \frac{8}{52}

P(E_{1}UE_{2})  ^{-} = \frac{52-8}{52} = \frac{44}{52} = 0.846

<u><em>Conclusion</em></u>:-

The probability of drawing the compliment of a king or a  queen from a standard deck of playing cards = 0.846

5 0
3 years ago
Help! The answer must me exact! Will rate you if correct!!
Maslowich

Answer:

The Correct Answer is 7.071

Step-by-step explanation:

Trust me, if its wrong report me, if its right mark me brinaliest pls

3 0
3 years ago
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