Answer:
5X + 8Y >= 300; intersection at (-20, 50)
Step-by-step explanation:
let t = work hours
0 < t < 30
X = time lawn mowing
Y = time babysitting.
X + Y < 30
5X + 8Y >= 300
We could solve...
X < 30 - Y
5(30 - Y) + 8Y >=300
150 - 5Y + 8Y >= 300
3Y >=150
Y >=50
then X < -20
intersection at (-20, 50)
Here is the answer to your question as This is the way I think it is solved
Answer:
the third one
Step-by-step explanation:
x^2 is always non-negative, so -3x^2 will always be non-positive. You can eliminate any tables with positive values for y.
Answer:
Option 1
Step-by-step explanation:
You must multiply (2x + 3) by (x + 4). I use the FOIL method.
(2x + 3)(x + 4)
Multiply
2x² + 8x +3x + 12
Simplify
2x² + 11x + 12
To check the answer, you could factor this trinomial back into a pair of binomials.
KCC
7 units 7-4=3 (-9)-(-5)=
-9+5=(-4)
3+(-4)= 7
