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Len [333]
4 years ago
9

A blimp is 1600 meters high in the air and measures the angles of depression to two stadiums to the east of the blimp. If those

measurements are 71.7° and 25.2°, how far apart are the two stadiums?
A. 3929 m
B. 3327 m
C. 3150 m
D. 2871 m

Mathematics
1 answer:
baherus [9]4 years ago
4 0
The explanation of the problem is as shown in the figure.
<span>A blimp     ⇒⇒⇒ point A
</span><span>stadium 1 ⇒⇒⇒ point B
</span><span>stadium 2 ⇒⇒⇒ point C
height of the blimp ⇒⇒⇒ AD = 1600
</span>depression angle of <span>stadium 1  ⇒⇒⇒ ∠y = </span><span>71.7°
</span>depression angle of <span>stadium 2  ⇒⇒⇒ ∠x = 25.2°
distance between </span><span><span>the two stadiums    ⇒⇒⇒ d

DC = AD * tan (90° - x) = 1600 * tan( 90° - 25.2° )
DB = AD * tan (90° - y) = 1600 * tan( 90° - 71.7° )

</span></span>∴ d = DC - DB
      = 1600 * [ tan( 90° - 25.2° ) - <span>tan( 90° - 71.7° ) ]
      = 2,871 </span><span>meters

</span>∴ The correct choice is option (D)



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