Ask question

Ask question

All categories

3 years ago

11

Six children collect 45 pencils. 20% of the pencils need sharpening. How many pencils need

2 answers:

egoroff_w [7]3 years ago

6 0

Answer:

9

Step-by-step explanation:

45*2/10=45*1/5=9

Ipatiy [6.2K]3 years ago

4 0

Answer:

9

Step-by-step explanation:

You might be interested in

Choose the equation that is the standard form of

Ronch [10]

For this case we have the following equations:
5y = 3-2x
5y-3 = -2x
2x + 5y = 3
2x + 5y-3 = 0
The standard form of the equations is given by:
Ax + By = C
Therefore, the equation written in its standard form is:
2x + 5y = 3
Where,
A = 2
B = 5
C = 3
Answer:
The equation that is the standard form is:
2x + 5y = 3

7 0

3 years ago

Roger has a credit card with an APR of 19.40% and a billing cycle of 30 days. The following table shows his transactions with th

Allushta [10]

Answer:

The daily balance method

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A sign in front of a roller coaster says "You must be 40 inches tall to ride."

Naya [18.7K]

Answer:

54/40 = 1.35 or 135%

Step-by-step explanation:

7 0

3 years ago

Charlotte bought 25 cookies to share with her class, and 5 of them are oatmeal raisin. What percent of the cookies are oatmeal r

LUCKY_DIMON [66]

Answer:

20%

Step-by-step explanation:

25 divided by 5 = 5

Convert to decimal

0.20

Convert to percentage

20%

7 0

3 years ago

Read 2 more answers

Find all solutions to the equation (x² + 5x + 6)(x² − 3x − 4) = 0.

Soloha48 [4]

Answer:

The solutions are:

$x=-2,\:x=-3,\:x=-1,\:x=4$

Step-by-step explanation:

To find the solutions to the equation $\left(x^2+5x+6\right)\left(x^2-3x-4\right)=0$ you need to:

Factor $\left(x^2+5x+6\right)$

Break the expression into groups

$x^2+5x+6=\left(x^2+2x\right)+\left(3x+6\right)$

Factor out $x$ from $(x^2+2x)$

$x^2+2x=x\left(x+2\right)$

Factor out 3 from $3x+6$

$3x+6=3\left(x+2\right)$

$x^2+5x+6=x\left(x+2\right)+3\left(x+2\right)\\\\\mathrm{Factor\:out\:common\:term\:}x+2\\\\x^2+5x+6=\left(x+2\right)\left(x+3\right)$

Factor $\left(x^2-3x-4\right)$

$x^2-3x-4=\left(x^2+x\right)+\left(-4x-4\right)\\\\x^2-3x-4=x\left(x+1\right)-4\left(x+1\right)\\\\x^2-3x-4=\left(x+1\right)\left(x-4\right)$

Therefore

$\left(x^2+5x+6\right)\left(x^2-3x-4\right)=\left(x+2\right)\left(x+3\right)\left(x+1\right)\left(x-4\right)=0$

Using the Zero Factor Theorem:

5 0

4 years ago