Question

Given: ΔАВС, m∠ACB = 90° CD ⊥ AB , m∠ACD = 60° BC = 6 cm Find CD, Area of ΔABC

Answer 1

Answer:

CD = 3√3 cm

Area  ΔABC =18cm²

Step-by-step explanation:

the angle  < ACB =90°

<ACD =60° therefore <BCD =30°

cos 30°= x/6

x= 3√3 cm

Area  ΔABC =1/2×base×height

the  ΔABC is a 45 45 90 triangle

: AC =6√3 cm

ΔABC = 1/2×6√3×6

ΔABC =18√3 cm²

Answer 2

Area=1/2*base*height
given that ABC is right angled triangle, the height will be given by:
tan theta=opposite/adjacent
tan 60=h/6
h=6tan60
=10.4
thus the area will be:
A=1/2x6x10.4
=31.2 cm^2