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3 years ago

Which fractions are equivalent to 4/9?

Mathematics

2 answers:

liubo4ka [24]3 years ago

7 0

Answer:

8/18, 12/27, 16/36, 20/45

LenaWriter [7]3 years ago

5 0

Answer:

$\frac{8}{18}$

Step-by-step explanation:

$\frac{4}{9} = \frac{4 \times 2}{9 \times 2} = \frac{8}{18} \\$

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Christopher borrowed $22,000 for 7 years. At the end of the loan, he had paid a total of $27,390. Find the interest rate on the

oee [108]

Step-by-step explanation:

okay so we know i = prt

in this scenario

p = 22,000

r = ?

t = 7

i = 27,390

the equation for r is (i/p*t)

so now let's plug in what we know

r = 27,390/22,000 * 7

r = 1.245 / 7

r = 8.715

please rate 5 stars and vote brainliest and say thanks

5 0

3 years ago

6. The sequence is recursive. Find the value of the next term in the sequence.

Alisiya [41]

Answer: the value is 30

Step-by-step explanation:

you are going up by 5 so 25+5 IS 30

CAN I HAVE BRAINLIEST PLEASE

8 0

3 years ago

Help me with part e please.

Andru [333]

I believe it would be 98

3 0

3 years ago

A finance company offers a 36-month installment loan with an APR of 10.5%. Jerry wishes to use the loan to finance an engagement

kumpel [21]

Well i’m not sure on this but i got 18 for my answer instead of 10 so if u need any mode help im here

8 0

3 years ago

Can you guys help me out on this? I'm still learning sign, cosign, and tangent :)

Yakvenalex [24]

Answer:

$\sin d = \frac{4}{7}$ ; $\sin e = \frac{\sqrt{33} }{7}$

$\cos d = \frac{\sqrt{33} }{7}$ ; $\cos e = \frac{4}{7}$

$\tan d = \frac{4}{\sqrt{33} }$ ; $\tan e = \frac{\sqrt{33} }{4}$

Step-by-step explanation:

For a right angled triangle with one of its angle α (alpha) :-

$\sin \alpha = \frac{Side \: opposite \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}$

$\cos \alpha = \frac{Side \: adjacent \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}$

$\tan \alpha = \frac{Side \: opposite \: to \: \alpha }{Side \: adjacent \: to \: \alpha }$

__________________________________________________

According to the question ,

1) When α (alpha) = d

$\sin d = \frac{4}{7}$

$\cos d = \frac{\sqrt{33} }{7}$

$\tan d = \frac{4}{\sqrt{33} }$

2) When α (alpha) = e

$\sin e = \frac{\sqrt{33} }{7}$

$\cos e = \frac{4}{7}$

$\tan e = \frac{\sqrt{33} }{4}$

3 0

3 years ago