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3 years ago

Can you help me with these questions???

Mathematics

1 answer:

lord [1]3 years ago

3 0

3. 28 Quarters and 5 dimes.

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Can someone help me with this or give me a link to the answers please

lana [24]

sorry it can't fit the other half

5 0

2 years ago

Does the function f(x) = 2x^2− 6x + 9 have a minimum or a maximum? Identify its value.

exis [7]

Answer:

minimum value of function is $\frac{45}{8}$ .

Step-by-step explanation:

Given function represents a parabola.

Now, here coefficient of $x^{2}$ is positive , so the parabola will be facing upwards and thus the function will be having a minimum.

Now, as we know that minimum value of a parabolic function occurs at

x = $\frac{-b}{4a}$ .

Where , b represents the coefficient of x and a represents the coefficient of $x^{2}$ .

here, a = 2 , b = -6

Thus $\frac{-b}{4a}$ = $\frac{6}{8}$

= $\frac{3}{4}$

So, at x = $\frac{3}{4}$ minimum value will occur and which equals

y = 2× $\frac{9}{16}$ - $\frac{18}{4}$ + 9 = $\frac{45}{8}$ .

Thus , minimum value of function is $\frac{45}{8}$ .

4 0

2 years ago

The graph below shows the distance, y, in miles, of a bird from its nest for a certain amount of time, x, in minutes:

Bogdan [553]

Answer:

Step-by-step explanation:

The y-intercept (0, 3) is initial value of graph ⇒ (d). <em>3 miles; it represents the original distance of the bird from its nest</em>

7 0

2 years ago

Read 2 more answers

A jet flies 405 miles in 5 hours. At this rate. how far could the jet fly in 15 hours? PLS

Marizza181 [45]

Answer: 1215 miles

Step-by-step explanation:

405 miles in 5 hours is 81 mph so you multiply that mph by the amount of hours you want (15) so 81 x 15 = 1215

3 0

3 years ago

What is the equation of the line that is perpendicular to y= -3x + 1 and passes through (2,3)?

Aleonysh [2.5K]

Answer:

$\large\boxed{y=\dfrac{1}{3}x+2\dfrac{1}{3}}$

Step-by-step explanation:

$\text{Let}\ k:y=_1x+b_1\ \text{and}\ l:y=m_2x+b_2.\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\============================\\\\\text{We have}\ y=-3x+1\to m_1=-3.\\\\\text{Therefore}\ m_2=-\dfrac{1}{-3}=\dfrac{1}{3}.\\\\\text{The equation of the searched line:}\ y=\dfrac{1}{3}x+b.\\\\\text{The line passes through }(2,\ 3).$

$\text{Put the coordinates of the point to the equation.}\ x=2,\ y=3:\\\\3=\dfrac{1}{3}(2)+b\\\\3=\dfrac{2}{3}+b\qquad\text{subtract}\ \dfrac{2}{3}\ \text{from both sides}\\\\b=2\dfrac{1}{3}$

3 0

3 years ago

Read 2 more answers