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sveta [45]
3 years ago
8

The temperature was-6F.It rose so that the temperature was 0F

Mathematics
1 answer:
qaws [65]3 years ago
8 0

Answer:

+6?

Step-by-step explanation:

Sorry I just don't understand what your question is...

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Estimate the total cost of 31 televisions at £196.50 each and 19 DVD players at £50.99 each
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Answer:

<h2><em>£</em><em>7</em><em>0</em><em>6</em><em>0</em><em>.</em><em>3</em><em>1</em></h2>

<em>Sol</em><em>ution</em><em>,</em>

<em>Cost</em><em> </em><em>of</em><em> </em><em>one</em><em> </em><em>telev</em><em>ision</em><em>=</em><em>£</em><em>1</em><em>9</em><em>6</em><em>.</em><em>5</em><em>0</em>

<em>cost</em><em> </em><em>of</em><em> </em><em>3</em><em>1</em><em> </em><em>televisions</em><em>:</em>

<em>= 196.50 \times 31 \\  = 6091.5</em>

<em>Cost</em><em> </em><em>of</em><em> </em><em>one</em><em> </em><em>DVD</em><em> </em><em>player</em><em>=</em><em>£</em><em>5</em><em>0</em><em>.</em><em>9</em><em>9</em>

<em>Cost</em><em> </em><em>of</em><em> </em><em>1</em><em>9</em><em> </em><em>DVD</em><em> </em><em>player</em><em>:</em>

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<em>=</em><em>6</em><em>0</em><em>9</em><em>1</em><em>.</em><em>5</em><em>+</em><em>9</em><em>6</em><em>8</em><em>.</em><em>8</em><em>1</em>

<em>=</em><em>£</em><em>7</em><em>0</em><em>6</em><em>0</em><em>.</em><em>3</em><em>1</em>

<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>

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neonofarm [45]
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\mathbf A=\begin{bmatrix}\mathbf a_1&\cdots&\mathbf a_n\end{bmatrix}

Then we have

\mathbf A^\top=\begin{bmatrix}\mathbf a_1&\cdots&\mathbf a_n\end{bmatrix}^\top

and the product of the two is

\mathbf A^\top\mathbf A=\begin{bmatrix}\mathbf a_1\cdot\mathbf a_1&\mathbf a_1\cdot\mathbf a_2&\cdots&\mathbf a_1\cdot\mathbf a_n\\\mathbf a_2\cdot\mathbf a_1&\mathbf a_2\cdot\mathbf a_2&\cdots&\mathbf a_2\cdot\mathbf a_n\\\vdots&\vdots&\ddots&\vdots\\\mathbf a_n\cdot\mathbf a_1&\mathbf a_n\cdot\mathbf a_2&\cdots&\mathbf a_n\cdot\mathbf a_n\end{bmatrix}

Because the columns of \mathbf A are orthonormal, we have

\mathbf a_i\cdot\mathbf a_j=\begin{cases}1&\text{for }i=j\\0&\text{for }i\neq j\end{cases}

which means \mathbf A^\top\mathbf A reduces to an n\times n matrix with ones along the diagonal and zero everywhere else, i.e.

\mathbf A^\top\mathbf A=\begin{bmatrix}1&0&\cdots&0\\0&1&\cdots&0\\\vdots&\vdots&\ddots&\vdots\\0&0&\cdots&1\end{bmatrix}=\mathbf I_n

where \mathbf I denotes the identity matrix. This means the solution to \mathbf{Ax}=\mathbf b is given by

\mathbf A^\top(\mathbf{Ax})=\mathbf A^\top\mathbf b\implies(\underbrace{\mathbf A^\top\mathbf A}_{\mathbf I})\mathbf x=\mathbf A^\top\mathbf b\implies\mathbf x=\mathbf A^\top\mathbf b
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Zarrin [17]

Answer: B

Step-by-step explanation:

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Step-by-step explanation:

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Bas_tet [7]

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Step-by-step explanation:

20/16

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