<span>Given a circle with radius r = 8 and a sector with subtended angle measuring 45°, find the area of the sector and the arc length.
They've given me the radius and the central angle, so I can just plug into the formulas. For convenience, I'll first convert "45°" to the corresponding radian value of π/4:
A = ((pi/4)/2)(8^2) = (pi/8)(8^2) = 8pi, s = (pi/4)(8) = 2pi
area A = 8π, arc-length s = 2π
Given a sector with radius r = 3 and a corresponding arc length of 5π, find the area of the sector.
For this exercise, they've given me the radius and arc length. From this, I can work backwards to find the subtended angle.
Then I can plug-n-chug to find the sector area.
5pi = (theta)(3), (theta) = (5/3)pi
So the central angle is (5/3)π.
Then the area of the sector is:
A = ((5/3)pi / 2)*(3^2) = ((5/6)pi)*(9) = (15/2)pi
A = (15 pi) / 2
</span><span>90/360 = 0.25 pi sq ft</span>
Answer:
Step-by-step explanation:
- The length of the segment JM is 25 units.
- The segment JL is between 0 and 12, so is 12 units.
- The segment KL is between 5 and 12, so is 7 units.
<u>The probabilities for each point:</u>
- P(point on JL) = 12/25
- P(point not on KL) = 1 - 7/25 = 18/25
<u>Required probability:</u>
- P = 12/25*18/25 = 216/625
Correct choice is D
6 x 7 = 42
And the missing number is 8, because 7 x 8 = 56.
Answer:
11 dimes, 17 nickels
Step-by-step explanation:
d + n = 28, put one variable by itself on a side, d = 28 - n
.10d + .05n = 1.95
Sub the first equation into the second
.10(28 - n) + .05n = 1.95
2.8 - .10n + .05n = 1.95
2.8 - .05n = 1.95
-.05n = -0.85
n = 17 nickels
d + 17 = 28
d = 11 11 dimes
The answer for this question would be 2 I think
