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Readme [11.4K]
3 years ago
7

Are these equivalent ratios? 24:32 and 18:24

Mathematics
2 answers:
ira [324]3 years ago
6 0

Answer:

Yes they are equal

Step-by-step explanation:

You can treat them like fractions and 24/32 =1/3

and 18/24 = 1/3

These can then put back into the ratios 1:3 and 1:3 which is the same

neonofarm [45]3 years ago
3 0
Yes 18:24 because I did the math on my computer
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X = y 2 - 1
pochemuha
Your answer would be option B. 2y² - y - 6 = 0. This is because if you were to substitute x = y² - 1 into the equation 2x - y = 4, you would get 2(y² - 1) - y = 4, which expands into 2y² - 2 - y = 4, and then simplifies to 2y² - y - 6 = 0.
I hope this helps!
7 0
3 years ago
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What is the equation in point slope form of the line that passes through the point (−1, −3) and has a slope of 4?
Dmitry_Shevchenko [17]

The point-slope form:

y-y_1=m(x-x_1)

We have the slope m = 4 and the point (-1, -3). Substitute:

y-(-3)=4(x-(-1))\\\\\boxed{y+3=4(x+1)}

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3 years ago
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Artemon [7]
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5 0
3 years ago
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To find the height of a pole, a surveyor moves 160 feet away from the base of the pole and then, with a transit 6 feet tall, mea
Artyom0805 [142]

Answer:

306.8 feet

Step-by-step explanation:

Refer the attached figure .

A surveyor moves 160 feet away from the base of the pole i.e. ED = 160 m

Referring the image .

AC=ED=160 m

A transit i.e. AE is 6 feet tall.

AE = CD=6 feet

With a transmit the angle of elevation to the top of the pole to be 62° i.e. ∠BAC = 62°

To Find BC , use tigonometric ratio.

Tan\theta = \frac{Perpendicular}{Base}

Tan 62^{\circ}=\frac{BC}{AC}

Tan 62^{\circ}=\frac{BC}{160}

1.88*160=BC

300.8=BC

Now, the height of the pole = BC+CD =300.8+6=306.8 feet

Hence the height of the pole is 306.8 feet

7 0
3 years ago
What is the area of the obtuse triangle given below?
Aloiza [94]

Answer:

C. 49 sq units

Step-by-step explanation:

Area of a triangle is

A = 1/2bh

base is 14 and height is 7

14 * 1/2 is 7

7*7 = 49

8 0
3 years ago
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