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Oksana_A [137]
3 years ago
12

A college bookstore marks up the price that it pays the publisher for a book by 40 %. If the selling price of a book is $ 81.00

comma how much did the bookstore pay for this​ book?
Mathematics
2 answers:
KengaRu [80]3 years ago
7 0

Answer:

32.40

Step-by-step explanation:

81 x 40% =48.60

81. -48.60 = 32.40

Lena [83]3 years ago
5 0

Answer:the college bookstore paid

$57.86 for the book.

Step-by-step explanation:

Let x represent the price that the college bookstore paid the publisher to get the book.

The college bookstore marks up the price by 40%. It means that the value of the mark up would be .40/100 × x = 0.4 × x = 0.4x

Therefore, the selling price of the book at the college bookstore would be

x + 0.4x = 1.4x

If the selling price of a book is $ 81.00, it means that

1.4x = 81

x = 81/1.4 = $57.86

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Step-by-step explanation:

Examining the response options:

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3 years ago
Help please?
Alla [95]
\bf \begin{array}{clclll}
3^{1001}&\qquad &4^{1002}\\
\uparrow &&\uparrow \\
a&&b
\end{array}\\\\
-----------------------------\\\\
(a+b)^2-(a-b)^2\implies (a^2+2ab+b^2)-(a^2-2ab+b^2)
\\\\\\
a^2+2ab+b^2-a^2+2ab-b^2\implies 2ab+2ab\implies 4ab
\\\\\\
now\qquad 4(3^{1001})(4^{1002})=k12^{1001}\qquad 
\begin{cases}
12^{1001}\\
(4\cdot 3)^{1001}\\
4^{1001}\cdot 3^{1001}
\end{cases}

\bf \\\\\\
4(3^{1001})(4^{1002})=k(4^{1001}\cdot 3^{1001})\implies \cfrac{4(3^{1001})(4^{1002})}{4^{1001}\cdot 3^{1001}}=k
\\\\\\
4\cdot \cfrac{3^{1001}}{3^{1001}}\cdot \cfrac{4^{1002}}{4^{1001}}=k\implies 4\cdot 4^{1002}4^{-1001}=k\impliedby 
\begin{array}{llll}
\textit{same base}\\
\textit{add the}\\
exponents
\end{array}
\\\\\\
4\cdot 4^{1002-1001}=k\implies 4\cdot 4^1=k\implies 16=k
6 0
3 years ago
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