Seven times ten thousand plus five times ten plus four times 1
Answer:
see explanation
Step-by-step explanation:
The area of the shaded portion is the area of the outer circle subtract the area of the inner circle
area of larger circle = πr² ← r is the radius = 11
area = π × 11² = 121π
area of smaller circle = πr² ← r = 9
area = π × 9² = 81π
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shaded area = 121π - 81π = 40π m² ≈ 126 m²
Answer:
A) B and C
Step-by-step explanation:
To find the perimeter, add up the lengths of all the sides.
For shape A: 16+16+1+1= 34
For shape B: 8+8+2+2= 20
For shape C: 5+5+5+5= 20
Shapes B and C both have a perimeter of 20. The answer is A, B and C.
I hope this helps!
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The other answer is not correct because they are finding the area of the rectangles.
Answer: Last Option
![4x^5\sqrt[3]{3x}](https://tex.z-dn.net/?f=4x%5E5%5Csqrt%5B3%5D%7B3x%7D)
Step-by-step explanation:
To make the product of these expressions you must use the property of multiplication of roots:
![\sqrt[n]{x^m}*\sqrt[n]{x^b} = \sqrt[n]{x^{m+b}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Em%7D%2A%5Csqrt%5Bn%5D%7Bx%5Eb%7D%20%3D%20%5Csqrt%5Bn%5D%7Bx%5E%7Bm%2Bb%7D%7D)
we also know that:
![\sqrt[3]{x^3} = x](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D%20%3D%20x)
So
![\sqrt[3]{16x^7}*\sqrt[3]{12x^9}\\\\\sqrt[3]{16x^3x^3x}*\sqrt[3]{12(x^3)^3}\\\\x^2\sqrt[3]{16x}*x^3\sqrt[3]{12}\\\\x^5\sqrt[3]{16x*12}\\\\x^5\sqrt[3]{2^4x*2^2*3}\\\\x^5\sqrt[3]{2^6x*3}\\\\4x^5\sqrt[3]{3x}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B16x%5E7%7D%2A%5Csqrt%5B3%5D%7B12x%5E9%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B16x%5E3x%5E3x%7D%2A%5Csqrt%5B3%5D%7B12%28x%5E3%29%5E3%7D%5C%5C%5C%5Cx%5E2%5Csqrt%5B3%5D%7B16x%7D%2Ax%5E3%5Csqrt%5B3%5D%7B12%7D%5C%5C%5C%5Cx%5E5%5Csqrt%5B3%5D%7B16x%2A12%7D%5C%5C%5C%5Cx%5E5%5Csqrt%5B3%5D%7B2%5E4x%2A2%5E2%2A3%7D%5C%5C%5C%5Cx%5E5%5Csqrt%5B3%5D%7B2%5E6x%2A3%7D%5C%5C%5C%5C4x%5E5%5Csqrt%5B3%5D%7B3x%7D)
