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Dmitry_Shevchenko [17]
3 years ago
15

Suppose S and T are mutually exclusive events. Find P(S or T)? sp(S) = 6/11 and p(t)= 1/10

Mathematics
1 answer:
Sholpan [36]3 years ago
3 0
Using P(A∪B) = P(A) + P (B) - P(A∩B) 
If we apply this in the question 
Then P(S∪T) = P(S) + P(T) - P (S∩T)
                      = 6/11 + 1/10 - P (S∩T)
                      = 71/110 - P (S∩T)
But events S and T are mutually exclusive events therefore, 
P(S∩T) = 0,
Hence P(S∪T) = 71/110
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Solution:

We have,

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x^2+13x+36=0

Splitting the middle term, we get

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