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3 years ago

Suppose S and T are mutually exclusive events. Find P(S or T)? sp(S) = 6/11 and p(t)= 1/10

1 answer:

3 0

Using P(A∪B) = P(A) + P (B) - P(A∩B)
If we apply this in the question
Then P(S∪T) = P(S) + P(T) - P (S∩T)
= 6/11 + 1/10 - P (S∩T)
= 71/110 - P (S∩T)
But events S and T are mutually exclusive events therefore,
P(S∩T) = 0,
Hence P(S∪T) = 71/110

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Rewrite 5/ 16 + 6/ 20 with a common denominator.

Troyanec [42]

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3 years ago

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Kryger [21]

Answer:

$m = \frac{2k}{v^{2} }$

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4 years ago

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Semmy [17]

Answer:

Period ⇒ 40

Amplitude ⇒ 12

Mid-line ⇒ 32

Step-by-step explanation:

The table is counting by 4's and the period is the amount of space between 2 peaks. In this scenario, we can find the peaks by looking for two of the same highest value (44). We can see that x=40 has a value of 44 while the other is actually not shown because it would be located at x=0. Therefore the period is 40

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The amplitude can be found by using the following:

$\frac{1}{2}|max - min|$

Our maximum is 44 and our minimum is 20.

$\frac{1}{2}|44 - 20|$

$\frac{1}{2}|24|$

$\frac{1}{2}(24)$

The amplitude is 12

The amplitude is the distance from the peak to the mid-line. To find the mid-line, we can either subtract our amplitude from our maximum value (44) or add our amplitude to our minimum value (20)

44 - 12 = 32

20 + 12 = 32

Therefore our mid-line is y = 32

~Hope this helps!~

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4 years ago

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Aleks [24]

Answer:

If we’re dividing .31 by 9

The solution is on the photo below

Hope this helped. Have a great day!