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enot [183]
3 years ago
8

Anyboady know (-3)-8​

Mathematics
1 answer:
cestrela7 [59]3 years ago
8 0

Answer:

−11

Step-by-step explanation:

−3−8

=−3−8

=−3+−8

=−11

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Ms. Garcia watched 6 commercials
Aleonysh [2.5K]

Answer:

15 commercials

Step-by-step explanation:

6 commercials --> 24 minute

x commercials --> 60 minute(1 hour)

x*24 = 6*60

clear x

x = (6*60)/24

x= 15

6 0
3 years ago
Maya has 28 apples, 12 oranges, and 8 mangos. She wants to put an equal number of each kind of fruit into baskets so all of the
marysya [2.9K]
12 in each basket.

28÷4= 7
12÷4= 3
8÷4=2
7+3+2= 12

Hope this helps!
4 0
3 years ago
Read 2 more answers
In August, James begins school shopping for his triplet daughters. One day, he bought 10 pairs of socks for $2.50 each and 3 pai
denpristay [2]

Answer:

2.50*10  350+d

Step-by-step explanation:

  • thats the answer up below
6 0
2 years ago
Before every​ flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the ai
ollegr [7]

Answer:

The probability that the aircraft  is  overload = 0.9999

Yes , The pilot has to be take strict action .

Step-by-step explanation:

P.S - The exact question is -

Given - Before every​ flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the aircraft. The aircraft can carry 37 ​passengers, and a flight has fuel and baggage that allows for a total passenger load of 6,216 lb. The pilot sees that the plane is full and all passengers are men. The aircraft will be overloaded if the mean weight of the passengers is greater than 6216/37 = 168 lb. Assume that weight of men are normally distributed with a mean of 182.7 lb and a standard deviation of 39.6.

To find - What is the probability that the aircraft is​ overloaded ?

         Should the pilot take any action to correct for an overloaded aircraft ?

Proof -

Given that,

Mean, μ = 182.7

Standard Deviation, σ = 39.6

Now,

Let X be the Weight of the men

Now,

Probability that the aircraft is loaded be

P(X > 168 ) = P(\frac{x - \mu}{\sigma} > \frac{168 - \mu}{\sigma} )

                 = P( z > \frac{168 - 182.7}{39.6} )

                 = P( z > -0.371)

                 = 1 - P ( z ≤ -0.371 )

                 = 1 - P( z > 0.371)

                 = 1 - 0.00010363

                 = 0.9999

⇒P(X > 168) = 0.9999

As the probability of weight overload = 0.9999

So, The pilot has to be take strict action .

5 0
2 years ago
What is the solution to x6 – 6x 5 + 15x 4 – 20x 3 + 15x 2 – 6x + 1 ≥ 0?
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Answer: C all real numbers

Step-by-step explanation:

I got the answer right on Edge

5 0
3 years ago
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