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xxTIMURxx [149]

3 years ago

11

You can model the entrance to a mine shaft using the equation

2 answers:

VLD [36.1K]3 years ago

8 0

Hey there,

<span>You can model the entrance to a mine shaft using the equation
y = − 2 (x + 4)(x − 4), where x and y are measured in feet. The x-axis represents
the ground. Find the width of the entrance at ground level.

Based by looking on this question above, your correct answer would be . . .

</span> $\boxed{y=8}$ and $\boxed{x=-1}$
<span>
Hope this helps.
~Jurgen</span>

Furkat [3]3 years ago

4 0

y=-1/2 2 (x+4)(x+-4+

-1/2*2 = -1

y=-1(x+4)(x-4)

solving for x

x - -4 and x =4

-4 to 4 = 8 feet

width = 8 feet

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9. When the sun makes an angle of o above the horizon, a building casts a shadow 17 feet long

Mkey [24]

Answer:

A. tan 38° = opposite/adjacent

opposite = (tan 38°)(adjacent)

opposite = (0.31)(17 ft)

opposite = 5.27 ft

B. height is = 5.27 ft

4 0

3 years ago

What is the value of a+1/a? when 5+5/a=10

GenaCL600 [577]

Answer:

I think 20 but i may of done my math wrong

Step-by-step explanation:

6 0

3 years ago

The volume of a rectangular prism whose dimensions are binomials with integer coefficients is modeled by the function V(x) = x^3

Levart [38]

Answer:

The missing dimension of the prism is (x-4)

Step-by-step explanation:

Here, we want to find the missing dimensions of the prism

To get the volume, we are to multiply three dimensions since we are talking about volume

Mathematically, to find the third dimension, we need to divide the original polynomial by the product of the two other dimensions

The product of the two other dimensions is;

(x-1)(x-9) = x^2-9x-x + 9

= x^2-10x+ 9

So we divide;

(x^3-14x^2+49x-36)/(x^2-10x+ 9)

We can use long division to get this

using long division, the answer here is x-4

5 0

3 years ago

Read 2 more answers

The diagram shows the curve with equation y = ( 1 + x ) cosx.

r-ruslan [8.4K]

Answer:

y = 1, 1.319, 1.024, 0

Step-by-step explanation:

Given equation:

$y=(1+x)\cos x$

$\textsf{when}\:x=0:$

$\begin{aligned} \implies y & =(1+0)\cos 0\\\implies y & = 1\end{aligned}$

$\textsf{when}\:x=\dfrac{\pi}{6}:$

$\begin{aligned} \implies y & =\left(1+\frac{\pi}{6}\right)\cos \left(\frac{\pi}{6}\right)\\\implies y & = 1.319\: \sf (3\:dp)\end{aligned}$

$\textsf{when}\:x=\dfrac{\pi}{3}:$

$\begin{aligned} \implies y & =\left(1+\frac{\pi}{3}\right)\cos \left(\frac{\pi}{3}\right)\\\implies y & = 1.024\: \sf (3\:dp)\end{aligned}$

$\textsf{when}\:x=\dfrac{\pi}{2}:$

$\begin{aligned} \implies y & =\left(1+\frac{\pi}{2}\right)\cos \left(\frac{\pi}{2}\right)\\\implies y & = 0\end{aligned}$

8 0

2 years ago

Which expressions are equivalent to 2-(-6+3)+4c

Artyom0805 [142]

Answer:

c. none of the above

Step-by-step explanation:

(-6+3)= -3

2--3=2+3=5

5+4c cant add them since they arent like terms

final answer 5+4c and that option isnt here

3 0

3 years ago