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xxTIMURxx [149]
3 years ago
11

You can model the entrance to a mine shaft using the equation

Mathematics
2 answers:
VLD [36.1K]3 years ago
8 0
Hey there,

<span>You can model the entrance to a mine shaft using the equation
y = − 2 (x + 4)(x − 4), where x and y are measured in feet. The x-axis represents
the ground. Find the width of the entrance at ground level. 

Based by looking on this question above, your correct answer would be . . .

</span>\boxed{y=8} and \boxed{x=-1}
<span>
Hope this helps.
~Jurgen</span>
Furkat [3]3 years ago
4 0

y=-1/2 2 (x+4)(x+-4+

-1/2*2 = -1

y=-1(x+4)(x-4)

solving for x

x - -4 and x =4

-4 to 4 = 8 feet

 width = 8 feet

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Step-by-step explanation:

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Sin tita= 0.6892.find the value Of tita correct to two decimal places<br><br>​
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Answer:

\theta \approx 6.28n + 2.38,  \quad  n \in \mathbb{Z}

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Considering \theta \in (0, 2\pi]

\theta \approx 2.38

or

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Step-by-step explanation:

\sin(\theta)=0.6892

We have:

\sin (x)=a \Longrightarrow x=\arcsin (a)+2\pi n \text{ or } x=\pi -\arcsin (a)+2\pi n \text{ as } n\in \mathbb{Z}

Therefore,

\theta= \arcsin (0.6892)+2\pi n, \quad n \in \mathbb{Z}

or

\theta = \pi -\arcsin (0.6892)+2\pi n, \quad  n\in \mathbb{Z}

---------------------------------

\theta \approx 6.28n + 2.38,  \quad  n \in \mathbb{Z}

or

\theta \approx 6.28n + 0.76, \quad n \in \mathbb{Z}

4 0
3 years ago
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Step-by-step explanation:

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