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12345 [234]
3 years ago
7

Help me with this ASAP pleaseeeeeee

Mathematics
1 answer:
Zina [86]3 years ago
4 0

Answer:

99

Step-by-step explanation:

You subtract 45 and 36 from 180

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Suppose an astronaut can jump vertically with an initial velocity of 5 m/s. The time that it takes him to touch the ground is gi
Vitek1552 [10]

Answer:

t=1.020s

Step-by-step explanation:

Given Equation:

5t-0.5at^{2} =0

Actually the given equation is the 2nd equation of motion

i.e. S =V_{i} t+0.5at^{2}

where S=0 because the astronaut jumps on the earth

and initial velocity V_{i}=5

to find time t, put the given value of a=9.8m/s^{2} in the given equation, we get

5t-0.5(9.8)t^{2} =0\\t(5-4.9t)=0\\ \ dividing\ both\ sides\ by\ t\ we \ get\\ 5-4.9t=0\\4.9t=5\\t=\frac{5}{4.9}\\ t=1.020s

it will take t=1.020s to reach the ground if he jumps on the Earth

3 0
3 years ago
Simplify the expression and show your work. 4y+5=-31
kondor19780726 [428]
4y +5=-31 \\ 
4y+5-5 = 31-5 \\ 
4y=-36 \\ 
4y/4=-36/4 \\ 
y=-9 \\ 
Check: \\ 
4(-9)+5=-31 \\ 
-36+5=-31 \\ 
-31=-31
3 0
3 years ago
Emily ran her first lap in 75 seconds she ran her second lap in 69 seconds using percentages how much better was her second lap
julsineya [31]

Answer:

Her second lap was <u>8%</u> better when compared to her first lap.

Step-by-step explanation:

Given:

Emily ran her first lap in 75 seconds she ran her second lap in 69 seconds.

Now, to find how much better was her second lap when compared to her first lap.

Emily ran her first lap in 75 seconds.

Emily ran her second lap in 69 seconds.

So, we get the difference in seconds:

75-69=6\ seconds.

<u><em>Thus, in her second lap she was 6 seconds better than first.</em></u>

Now, to get the percentage of her first lap better than second:

\frac{6}{75}\times 100

=0.08\times 100

=8\%.

Therefore, her second lap was 8% better when compared to her first lap.

7 0
3 years ago
A financial analyst wanted to estimate the mean annual return on mutual funds. A random sample of funds' returns shows an averag
Feliz [49]

A financial analyst wanted to estimate the mean annual return on mutual funds. A random sample of 60 funds' returns shows an average rate of 12%. If the population standard deviation is assumed to be 4%, the 95% confidence interval estimate for the annual return on all mutual funds is

A. 0.037773 to 0.202227

B. 3.7773% to 20.2227%

C. 59.98786% to 61.01214%

D. 51.7773% to 68.2227%

E. 10.988% to 13.012%

Answer: E. 10.988% to 13.012%

Step-by-step explanation:

Given;

Mean x= 12%

Standard deviation r = 4%

Number of samples tested n = 60

Confidence interval is 95%

Z' = t(0.025)= 1.96

Confidence interval = x +/- Z'(r/√n)

= 12% +/- 1.96(4%/√60)

= 12% +/- 0.01214%

Confidence interval= (10.988% to 13.012%)

3 0
3 years ago
A line passes through the point (9,1) and has a slope of 2.Write an equation in slope-intercept form for this line.
bogdanovich [222]

Answer:

y = 2x-17

Step-by-step explanation:

We have a point and a slope, we can write the equation in point slope form and then convert to slope intercept form

y-y1 = m(x-x1) where m is the slope and (x1,y1) is the point

y-1 = 2(x-9)

Distribute

y-1=2x-18

Add 1 to each side

y-1+1 = 2x-18+1

y = 2x-17

This is slope intercept form

4 0
3 years ago
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