<h2><u>
Answer with explanation</u>
:</h2>
Let
be the distance traveled by deluxe tire .
As per given , we have
Null hypothesis : 
Alternative hypothesis : 
Since
is left-tailed and population standard deviation is known, thus we should perform left-tailed z-test.
Test statistic : 
where, n= sample size
= sample mean
= Population mean
=sample standard deviation
For
, we have

By using z-value table,
P-value for left tailed test : P(z≤-2.23)=1-P(z<2.23) [∵P(Z≤-z)=1-P(Z≤z)]
=1-0.9871=0.0129
Decision : Since p value (0.0129) < significance level (0.05), so we reject the null hypothesis .
[We reject the null hypothesis when p-value is less than the significance level .]
Conclusion : We do not have enough evidence at 0.05 significance level to support the claim that t its deluxe tire averages at least 50,000 miles before it needs to be replaced.
After the first, we have 2/3 left, the second and third took 1/6 and 1/4, or 5/12 (1/6+1/4=2/12+3/12=(2+3)/12=5/12). Now, we just subtract 5/12 from 2/3, so 2/3-5/12=8/12-5/12=(8-5)/12=3/12=1/4. This means we have 1/4 of an hour left.
Answer:
Infinite.
Step-by-step explanation:
3(x+1)-5=3x-2
3x+3-5=3x-2
3x-2=3x-2
True for any number.