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3 years ago

- a - 5 + 12a - 9 + 7

1 answer:

5 0

The answer is 11a -7 don’t go on brainly for math problems go on photo math. On photo math all you have to do is take a pic of the equation and it will answer it to you right away.

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Divide these numbers.<br><br> 18 ÷ 4

irakobra [83]

Answer:

4.5

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A bag contains 100 cubes that are black, yellow, and white. A student randomly selects a cube without looking and replaces it in

I am Lyosha [343]

Answer:

The answer is..

A) 45 black cubes

B) 20 yellow cubes

E) 35 white cubes

Step-by-step explanation:

4 0

3 years ago

X^2 + y^2=40 and y=x-4 solve this simultaneous equation

inn [45]

Write x-4 instead of y.
x²+(x-4)²=40
x²+x²-8x+16=40
2x²-8x-24=0
x²-4x-12=0
(x-6)(x+2)=0
x=6 or x=-2

for x=6, y=6-4 = 2
for x=-2, y=-2-4 = -6

3 0

3 years ago

Help with both plz I’ll mark brainliest

LekaFEV [45]

Answer:

(1,6) is not a solution and I think the second one is: c I think

Step-by-step explanation:

5 0

2 years ago

The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d

jek_recluse [69]

Answer:

50%

Step-by-step explanation:

68-95-99.7 rule

68% of all values lie within the 1 standard deviation from mean $(\mu-\sigma,\mu+\sigma)$

95% of all values lie within the 1 standard deviation from mean $(\mu-1\sigma,\mu+1\sigma)$

99.7% of all values lie within the 1 standard deviation from mean $(\mu-3\sigma,\mu+3\sigma)$

The distribution of the number of daily requests is bell-shaped and has a mean of 55 and a standard deviation of 4.

$\mu = 55\\\sigma = 4$

68% of all values lie within the 1 standard deviation from mean $(\mu-\sigma,\mu+\sigma)$ = $(55-4,55+4)$ = $(51,59)$

95% of all values lie within the 2 standard deviation from mean $(\mu-1\sigma,\mu+1\sigma)$ = $(55-2(4),55+2(4))$ = $(47,63)$

99.7% of all values lie within the 3 standard deviation from mean $(\mu-3\sigma,\mu+3\sigma)$ = $(55-3(4),55+3(4))$ = $(43,67)$

Refer the attached figure

P(43<x<55)=2.5%+13.5%+34%=50%

Hence The approximate percentage of light bulb replacement requests numbering between 43 and 55 is 50%

4 0

3 years ago