Please help me with this!

Solve 2x - 8 + 3x > 5x - 4 also if you can plz explain

WITCHER [35]

Answer:

No solution

Step-by-step explanation:

2x - 8 + 3x > 5x - 4

2x + 3x - 8 > 5x - 4

5x - 8 > 5x - 4

-5x +8 > -5x +8

----------------------

0x > 4

This is no solution, as there is no 'x' value.

(0x just means there isn't anything left, I put that in order to show there wasn't anything.)

7 0

3 years ago

Please help 6x + 32 = -2x

netineya [11]

Answer: the answer is x=-4.

Step-by-step explanation:

5 0

1 year ago

If m = 5 and n = -2, evaluate 3m - 4n and n2 - m and find the product of the two expressions.

ddd [48]

Hence the correct answer is C) -23

Further explanation:

We have to put the values of m and n into both expression first separately and then multiply the answers.

Given expressions are:

$Exp\ 1:3m-4n\\Exp\ 2: n^2-m$

The values are:

$m=5\\n=-2$

Putting the values in expression 1:

$3m-4n\\=3(5)-4(-2)\\=15+8\\=23$

Putting the values of m and n in second expression

$n^2-m\\=(-2)^2-5\\=4-5\\=-1$

Multiplying both expressions:

$(3m-4n)(n^2-m)=23* (-1)=-23$

Hence the correct answer is C) -23

Keywords: Polynomials, Putting values in expressions

Learn more about polynomials at:

#LearnwithBrainly

8 0

3 years ago

Find f. A) 7.4 B) 8.2 C) 10.5 D) 11.1

tatyana61 [14]

F=72

g=6

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$\cos { \left( F \right) } =\frac { { e }^{ 2 }+{ g }^{ 2 }-{ f }^{ 2 } }{ 2eg }$

Therefore:

$\cos { \left( 72 \right) } =\frac { { e }^{ 2 }+{ 6 }^{ 2 }-{ f }^{ 2 } }{ 2\cdot e\cdot 6 } \\ \\ \cos { \left( 72 \right) } =\frac { { e }^{ 2 }+36-{ f }^{ 2 } }{ 12e }$

$\\ \\ 12e\cdot \cos { \left( 72 \right) } ={ e }^{ 2 }+36-{ f }^{ 2 }\\ \\ \therefore \quad { f }^{ 2 }={ e }^{ 2 }-12e\cdot \cos { \left( 72 \right) } +36\\ \\ \therefore \quad f=\sqrt { { e }^{ 2 }-12e\cdot \cos { \left( 72 \right) +36 } } \\ \\ \therefore \quad f=\sqrt { e\left( e-12\cos { \left( 72 \right) } \right) +36 }$

But what is e?

E=76

G=32

g=6

And:

$\frac { e }{ \sin { \left( E \right) } } =\frac { g }{ \sin { \left( G \right) } }$

Which means that:

$\frac { e }{ \sin { \left( 76 \right) } } =\frac { 6 }{ \sin { \left( 32 \right) } } \\ \\ \therefore \quad e=\frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } }$

If you take this value into account, you will discover that f is...

$f=\sqrt { \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } \left( \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } -12\cos { \left( 72 \right) } \right) +36 } \\ \\ \therefore \quad f=10.8\quad \left( 1\quad d.p \right)$

So I would have to say that the answer is approximately (c).

6 0

3 years ago

Which goes in which order

velikii [3]

4 x (3+6) = 12 + 24 ---->Distributive

3 + ( 8 + 2) = 3 + (2 + 8) ---> Commutative

6 x (7 x 3 ) = (6 x 7 ) x 3 --->Associative

8 0

3 years ago

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