All categories

3 years ago

Why must integration be used to find the work required to pump water out of a tank?

Mathematics

1 answer:

Anton [14]3 years ago

7 0

Answer:

A. Different volumes of water are moved different distances.

Step-by-step explanation:

Integration is used to find work required to pump water out of a tank because different volumes of water are moved different distances and to sum it all we the tool required is integration. Moreover, work done is a path function or an inexact differential. It does depend upon the path followed by the process.

hence the correct answer is A.

You might be interested in

NEED EVIDENCE NOT JUST ANSWER There are 540 grams of sugar in 5 liters of soda. how many grams of sugar are in 3 liters of soda?

Ad libitum [116K]

<h3>Answer: 324 grams</h3>

Work Shown:

(540 grams sugar)/(5 liter soda) = (x grams sugar)/(3 liter soda)

540/5 = x/3

540*3 = 5*x

1620 = 5x

5x = 1620

x = 1620/5

x = 324

3 liters of soda has 324 grams of sugar

8 0

3 years ago

The perimeter of a rectangle is 20xm. the length is 6cm longer than the width. what are the length and width of the rectangle?

aleksley [76]

Let width be x

length= 6+x

p=2(l+w)
20=2(6+x+x)
10=2x+6
10-6=2x
4=2x
x=4/2
x=2

Therefore the width is 2 cm and length is (6+2)= 8 cm

Hope I helped :)

3 0

3 years ago

Read 2 more answers

Can someone plz help with these :)

77julia77 [94]

1. Odd
2. Neither
3. Even
4. Odd
5. Neither
6. Even

5 0

3 years ago

Intercept from a table

gladu [14]

$\bf \begin{array}{ccll} x&y\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ \boxed{14}&\boxed{-5}\\ 21&-3\\ \boxed{28}&\boxed{-1} \end{array}\impliedby \textit{we'll use two points to get the slope}$

$\bf (\stackrel{x_1}{14}~,~\stackrel{y_1}{-5})\qquad (\stackrel{x_2}{28}~,~\stackrel{y_2}{-1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-(-5)}{28-14}\implies \cfrac{-1+5}{28-14} \\\\\\ \cfrac{4}{14}\implies \cfrac{2}{7} \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-5)=\cfrac{2}{7}(x-14) \\\\\\ y+5=\cfrac{2}{7}x-4$

now, to get the y-intercept, we simply set x = 0 and solve for y, and to get the x-intercept, we set y = 0 and solve for x.

$\bf \stackrel{\textit{y-intercept, x = 0}}{y+5=\cfrac{2}{7}(0)-4}\implies y+5=-4\implies y=-9\qquad \qquad \stackrel{y-intercept}{(0~,-9)}\\\\ -------------------------------\\\\ \stackrel{\textit{x-intercept, y = 0}}{(0)+5=\cfrac{2}{7}x-4}\implies 5=\cfrac{2x}{7}-4\implies 9=\cfrac{2x}{7}\implies 63=2x \\\\\\ \cfrac{63}{2}=x\implies 31\frac{1}{2}=x\qquad \qquad \qquad \qquad \qquad \qquad \qquad \stackrel{x-intercept}{\left( 31\frac{1}{2}~,~0 \right)}$

8 0

3 years ago

What type of chart would best be used for continuous data?

andriy [413]

Histogram charts are best used for continuous data

6 0

3 years ago

Why must integration be used to find the work required to pump water out of a​ tank?

Why must integration be used to find the work required to pump water out of a tank?