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PtichkaEL [24]
3 years ago
7

What’s the solution ??

Mathematics
1 answer:
allochka39001 [22]3 years ago
8 0

Answer:

(5,-2)

Step-by-step explanation:

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What is the area of 1.7 km and 2.5 km? ___ square kilometers
Kaylis [27]

Answer:

4.15 km.

Step-by-step explanation:

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SOMEONE PLS HELP MEE ASAPPP!!
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I think you would just add 2/3 and 1/3 to get 1 full can of paint. If not sorry.

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Given the parent function f(x) = x², define the function g(x) that
Bas_tet [7]

Answer:

Part 1) g(x)=-x^{2}

Part 2) g(x)=(x+3)^{2}

Part 3) g(x)=x^{2}+7

Step-by-step explanation:

we have

The parent  function is f(x)=x^{2}

This is a vertical parabola open upward with vertex at origin (0,0)

Part 1) Reflection over the x-axis

The rule of the reflection across the x=axis is equal to

(x,y) ------> (x,-y)

so

f(x) -----> g(x)

The function g(x) will be

g(x)=-x^{2}

Part 2) Horizontal shift left 3 units

The rule of the translation is

(x,y) ------> (x-3,-y)

so

f(x) -----> g(x)

The function g(x) will be

g(x)=(x+3)^{2}

Part 3) Vertical shift up 7 units

The rule of the translation is

(x,y) ------> (x,y+7)

so

f(x) -----> g(x)

The function g(x) will be

g(x)=x^{2}+7

5 0
3 years ago
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A log is 20 m long, correct to the nearest metre.
Marat540 [252]

Answer:

222 fence posts

Step-by-step explanation:

Since the log is 20 m long, correct to the nearest metre and has to be cut into fence posts which must be 90 cm long, correct  to the nearest 10 centimetres, there can be x fence posts 90 cm long.

So, we have x × 90 cm = 20 m

x × 0.9 m = 20 m

x = 20 m/0.9 m

x = 222.22

x ≅ 222 fence posts

So, the largest number of fence posts that can possibly be cut from the log is 222 fence posts.

4 0
3 years ago
The average human heart beats 1.15 \cdot 10^51.15⋅10 5 1, point, 15, dot, 10, start superscript, 5, end superscript times per da
andriy [413]

Answer:

4.1975\cdot 10^{7}

Step-by-step explanation:

We are told that the average human heart beats 1.15\cdot 10^{5} times per day and there are 3.65\cdot 10^{2} days in one year.

To find number of heart beats in one year we will multiply number of heart beats in one day by number of days in one year.

1.15\cdot 10^{5}\times 3.65\cdot 10^{2}

Now we will solve this problem using exponent properties.

1.15 \times 3.65\cdot 10^{2+5}

1.15 \times 3.65\cdot 10^{7}

4.1975\cdot 10^{7}

Our answer is in scientific notation we can represent it in standard form as 4.1975\cdot 10^{7}=4.1975*10000000=41975000 times.

Therefore, average human heart beats in one year 4.1975\cdot 10^{7} or 41975000 times.

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