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3 years ago

I need to know answer to my math question

Mathematics

1 answer:

levacccp [35]3 years ago

3 0

I don't see the question . What is the question

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Megan has a piece of fabric which is a right triangular shape. The length of leg 1 is 4 m. The length of the other leg is twice

Bess [88]

Answer:

8.94 m

Step-by-step explanation:

Use the Pythagorean Theorum - $a^2 + b^2 = c^2$ . Use leg 1 as a, leg 2 as b, and the third side as c.

We know leg 1 is 4, and that leg 2 is twice as long as leg 1...

$(4)^2 + (4*2)^2 = c^2$

Now, we use the Order of Operations to find $c^2$ ...

$4^2+8^2=c^2\\16+64=c^2\\80=c^2$

Now, we find the square root of $c^2$ to find c...

$\sqrt{80} =8.94$

So, the length of the third side is 8.94 m.

8 0

3 years ago

Solve the equation 18=-5(4x+3)+21x

AlexFokin [52]

$-5(4x+3)+21x=18\\\\(-5)(4x)+(-5)(3)+21x=18\\\\-20x-15+21x=18\ \ \ |+15\\\\x=33$

5 0

3 years ago

An obtuse triangle has two angles 45 n 18 ,and a third unknown angle theta what's the value of the unknown angle

zlopas [31]

Answer:

An obtuse triangle has two angles 45 and 18. The value of the unknown angle is $117^{\circ}$

Solution:

Given that two angles of an obtuse triangle is 45 and 18.

Third angle is θ

We are asked to find the value of third unknown angle theta

According to angle sum property of triangle, sum of three angles of triangle is $180^{\circ}$

This means in our case sum of 45, 18 and θ should be $180^{\circ}$

$\begin{array}{l}{=>45+18+\theta=180} \\ {=>\theta=180-63=117^{\circ}}\end{array}$

Hence value of unknown third angle of an obtuse triangle is $117^{\circ}$

7 0

4 years ago

Please help me and I’ll give you brainiest!!!!!!!!!

Aleksandr-060686 [28]

Answer:

Graph it on a graphing calculator

Step-by-step explanation:

6 0

3 years ago

BRAINLIEST FOR BEST ANSWER!!!

sertanlavr [38]

less than; Set A

It is less than, because if you add half of the sum of the least and greatest numbers of the set to the lowest number in the set, you get the median. The median of Set A was 17, and the Median of Set B was 17.5.

Set A is more variable in terms of range, because it has a larger range.

4 0

3 years ago