Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
30=12m
you divide both sides by 12
so 30/12 is 2.5
Answer:
-2x + 6
Step-by-step explanation:
Step 1: Define
f(x) = 3x + 2
g(x) = 4 - 5x
Step 2: Find f(x) + g(x)
3x + 2 + 4 - 5x
-2x + 6
- 5/12 + ( - 1/4) =
Adding two negatives results in a negative
-1/4 = -3/12
-3/12 + -5/12 = -8/12
-8/12 + 3/12 < Subtract and take the sign of the BIGGER number.
8 - 3 = 5
- 5/12
Answer: - 5/12
