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Valentin [98]
4 years ago
6

Complete the equation of the line through (-8,8) and (1,-10)

Mathematics
1 answer:
zysi [14]4 years ago
4 0

Answer:

\[y+2x=-8\]

Step-by-step explanation:

The equation of a line passing through two given points (x1,y1) and (x2,y2) is given by:

\[\frac{(x-x1)}{(x2-x1)}=\frac{(y-y1)}{(y2-y1)}\]

In this case, x1=-8,y1=8,x2=1,y2=-10

Substituting these values in the equation:

\[\frac{(x-(-8))}{(1-(-8))}=\frac{(y-8)}{(-10-8)}\]

Simplifying,

\[\frac{(x+8)}{(1+8)}=\frac{(y-8)}{(-18)}\]

=> \[\frac{(x+8)}{9}=\frac{(y-8)}{(-18)}\]

=> \[\frac{(x+8)}{9}*(-18)=(y-8)\]

=> \[-2x-16=y-8\]

=> \[-8=y+2x\]

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Step-by-step explanation:

By the geometric mean theorem,

\sqrt{8k}=4\\\\8k=16\\\\k=\boxed{2}

6 0
2 years ago
Solve the following compound inequality: 4 less-than-or-equal-to x + 4 less-than-or-equal-to 12. a. 0 less-than-or-equal-to x le
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Answer:

A. 0 <= x <= 8

Step-by-step explanation:

4 <= x + 4 <= 12

Remove 4 from all sides

4 - 4 <= x + 4 -4 <= 12 - 4

0 <= x <= 8

7 0
2 years ago
An=an-1+6an-2 <br> n&gt;2 a0=3 a1=6
Svetach [21]
\begin{cases}a_0=3\\a_1=6\\a_n=a_{n-1}+6a_{n-2}&\text{for }n>2\end{cases}

Let the generating function for a_n be

A(x)=\displaystyle\sum_{n\ge0}a_nx^n

Multiplying both sides by x^{n-2}

a_nx^{n-2}=a_{n-1}x^{n-2}+6a_{n-2}x^{n-2}

Summing both sides over the non-negative integers greater than or equal to 2 gives

\displaystyle\sum_{n\ge2}a_nx^{n-2}=\sum_{n\ge2}a_{n-1}x^{n-2}+6\sum_{n\ge2}a_{n-2}x^{n-2}
\displaystyle\frac1{x^2}\sum_{n\ge2}a_nx^n=\frac1x\sum_{n\ge1}a_nx^n+6\sum_{n\ge0}a_nx^n
\displaystyle\frac1{x^2}\left(\sum_{n\ge0}a_nx^n-a_0-a_1x\right)=\frac1x\left(\sum_{n\ge0}a_nx^n-a_0\right)+6\sum_{n\ge0}a_nx^n
\displaystyle\frac1{x^2}\left(A(x)-3-6x\right)=\frac1x\left(A(x)-3\right)+6A(x)
A(x)=\dfrac{3x+3}{1-x-6x^2}
A(x)=\dfrac3{5(1+2x)}+\dfrac{12}{5(1-3x)}

For |x|, the two series converge to

\displaystyle A(x)=\frac35\sum_{n\ge0}(-2x)^n+\frac{12}5\sum_{n\ge0}(3x)^n
\implies A(x)=\displaystyle\sum_{n\ge0}\dfrac{3(-2)^n+12(3)^n}5x^n
a_n=\dfrac{3(-2)^n+12(3)^n}5=\dfrac{3(-2)^n+4(3)^{n+1}}5
5 0
3 years ago
Need help ASAP! Will mark brainliest
Alex777 [14]

Answer:

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7 0
3 years ago
X to the second power is 49 what is x?
agasfer [191]
X=7 because 7 squared equals 49
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3 years ago
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