Shanee bikes 5 miles to the park in 30 minutes and 3 miles to the library in 45 minutes. What was her average speed?

Write 18,801,310 in expanded form using exponents

Gnesinka [82]

Answer:

Quite a long one, here it is:

18,801,310 = (1 x $10^{9}$ ) + (8 x $10^{8}$ ) + (0 x $10^{7}$ ) + (8 x $10^{6}$ ) + (0 x $10^{5}$ ) + (1 x $10^{4}$ ) + (0 x $10^{3}$ ) + (3 x $10^{2}$ ) + (1 x $10^{1}$ ) + (0 x $10^{0}$ )

Additionally, if you can't copy that and you needed to use the caret key (^) instead of the exponent image on brainly here it is:

18,801,310 = (1 x 10^9) + (8 x 10^8) + (0 x 10^7) + (8 x 10^6) + (0 x 10^5) + (1 x 10^4) + (0 x 10^3) + (3 x 10^2) + (1 x 10^1) + (0 x 10^0)

Hope this helps and have a nice day!

8 0

3 years ago

The two triangles are similar. Solve for x.

Alenkasestr [34]

Answer:

Here Two triangles BDE and BAC are similar as mentioned

So, According to Similarity of triangles theorem

BE/BC = DE/AC

4/16= x/20

1/4 = x/20

x= 20/4

x=5

5 0

3 years ago

How do you simplify sin^4-cos^4=2sin^2-1?

Naily [24]

$\bf \textit{Double Angle Identities} \\\\ cos(2\theta)= \begin{cases} cos^2(\theta)-sin^2(\theta)\\ 1-2sin^2(\theta)\\ 2cos^2(\theta)-1 \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \begin{array}{llll} sin^4(\theta )-cos^4(\theta )&=&2sin^2(\theta )-1\\[1em] [sin(\theta )]^4-[cos(\theta )]^4&=&-[1-2sin^2(\theta )]\\[1em] \stackrel{\textit{difference of squares}}{[[sin(\theta )]^2]^2-[[cos(\theta )]^2]^2}&=&-[cos^2(\theta )-sin^2(\theta )]\\[1em] [sin^2(\theta )-cos^2(\theta )][sin^2(\theta )+cos^2(\theta )]&=&sin^2(\theta )-cos^2(\theta )\\[1em] [sin^2(\theta )-cos^2(\theta )][1]&=\\\\ sin^2(\theta )-cos^2(\theta ) &=\end{array}$

8 0

2 years ago

Shrinivas deposited $1300 in an account which pays 8% annual interest, compounded continuously. How long will it take to reach $

sertanlavr [38]

Answer: a. 12.4 years

Step-by-step explanation:

Function to represent exponential growth continuously:

$A=A_0e^{rt}$ ...(i)

, where $A_0$ = initial amount, r= rate of interest ( in decimal) , A = Amount after t years.

As per given , we have

$A_0=\$1300\\\\r=8\%=0.08\\\\ A=\$3500$

To find : t

Put all values in (i) ,

$3500=(1300)e^{0.08t}\\\\\Rightarrow\ 2.6923077=e^{0.08t}$

Taking natural log on both sides

$\ln(2.6923076)= 0.08t\\\\\Rightarrow\ 0.99039867=0.08t\\\\\Rightarrow\ t=\dfrac{0.99039866}{0.08}=12.37998325\approx12.4$

Hence, it would take 12.4 years.

so, the correct option is a. 12.4 years .

8 0

3 years ago

Can someone solve, explain and show their work? I don't understand why my answers are wrong.

neonofarm [45]

Multiply 14 (the price of gas in 2000) by 19.9% (the price as a percentage of the 2000 price). 14 times 0.199 is 2.786. Therefore, it would cost $2.79 to fill the same gas tank in 1960.

Not 100% sure if this answer is correct, but this is what I got.

6 0

3 years ago