The kinetic energy (in joules) of a moving
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Hello there,
So we are trying to find out is the angle ∠BAC in degrees.
So what we are going to do is. . .25- (2x-10)°.
That answer would be -2x+35.
So ∠BAC= -2x+35°.
Hope this helps.
~Jurgen
So we are trying to find out is the angle ∠BAC in degrees.
So what we are going to do is. . .25- (2x-10)°.
That answer would be -2x+35.
So ∠BAC= -2x+35°.
Hope this helps.
~Jurgen