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lilavasa [31]
3 years ago
14

WILL GIVE BRAINLIEST!!! Question in pic!!!!! Help pls!!

Mathematics
2 answers:
andriy [413]3 years ago
7 0

Answer:

y=11

x= 26

Step-by-step explanation:

aalyn [17]3 years ago
3 0

Answer:

x=26

y=11

Step-by-step explanation:

y is equal to the one on the opposite side, so y=11

since 24 and the other side are equal, and the other side is x-2, you do 24+2=26

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Cellus
Solnce55 [7]

Answer:

<6

Step-by-step explanation:

Corresponding angles have the same matching corner.

<6 has the same matching corner as <2. <6 and <2 are congruent.

Therefore, it can be concluded that <6 corresponds to <2.

6 0
3 years ago
Mr. Flores has 100 pictures in a photo album. Of these pictures, 20 show his friends, 50 show his family, and 30 show his pet da
saw5 [17]

Answer:

false

Step-by-step explanation:

just trust me

8 0
3 years ago
I rlly need help!!!!!!!
Yuliya22 [10]
The correct answer is the 2nd one
3 0
2 years ago
Consider a rabbit population​ P(t) satisfying the logistic equation StartFraction dP Over dt EndFraction equals aP minus bP squa
maria [59]

Solution:

Given :

$\frac{dP}{dt}= aP-bP^2$         .............(1)

where, B = aP = birth rate

            D = $bP^2$  =  death rate

Now initial population at t = 0, we have

$P_0$ = 220 ,  $B_0$ = 9 ,  $D_0$ = 15

Now equation (1) can be written as :

$ \frac{dP}{dt}=P(a-bP)$

$\frac{dP}{dt}=bP(\frac{a}{b}-P)$    .................(2)

Now this equation is similar to the logistic differential equation which is ,

$\frac{dP}{dt}=kP(M-P)$

where M = limiting population / carrying capacity

This gives us M = a/b

Now we can find the value of a and b at t=0 and substitute for M

$a_0=\frac{B_0}{P_0}$    and     $b_0=\frac{D_0}{P_0^2}$

So, $M=\frac{B_0P_0}{D_0}$

          = $\frac{9 \times 220}{15}$

          = 132

Now from equation (2), we get the constants

k = b = $\frac{D_0}{P_0^2} = \frac{15}{220^2}$

        = $\frac{3}{9680}$

The population P(t) from logistic equation is calculated by :

$P(t)= \frac{MP_0}{P_0+(M-P_0)e^{-kMt}}$

$P(t)= \frac{132 \times 220}{220+(132-220)e^{-\frac{3}{9680} \times132t}}$

$P(t)= \frac{29040}{220-88e^{-\frac{396}{9680} t}}$

As per question, P(t) = 110% of M

$\frac{110}{100} \times 132= \frac{29040}{220-88e^{\frac{-396}{9680} t}}$

$ 220-88e^{\frac{-99}{2420} t}=200$

$ e^{\frac{-99}{2420} t}=\frac{5}{22}$

Now taking natural logs on both the sides we get

t = 36.216

Number of months = 36.216

8 0
3 years ago
Choose the best description of the relationship between the data in the scatter plot.
Ulleksa [173]
The answer to your question is D
7 0
3 years ago
Read 2 more answers
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