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svlad2 [7]
3 years ago
5

A newspaper and three hot chocolates cost $7. Two newspapers and two hot chocolates cost $6. How much does one hot chocolate cos

t?
Mathematics
1 answer:
pochemuha3 years ago
3 0

Answer:

the cost of one hot chocolate is $2.

Step-by-step explanation:

Let x be the hot chocolate cost and y be the newspaper cost.

Given:

A newspaper and three hot chocolates cost $7

So, the equation is

3x+y=7--------(1)

Two newspapers and two hot chocolates cost $6

So, the second equation is.

2x+2y=6---------(2)

Find one hot chocolate cost?

Solve equation 1 for y.

3x+y=7

y=7-3x

Put y value in equation 2

2x+2(7-3x)=6

2x+14-6x=6

14-4x=6

-4x=6-14

-4x=-8

negative sign is cancelled both side.

x=\frac{8}{4}

x=2

Therefore, the cost of one hot chocolate is $2.

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Answer:

W(t) = 10 + 1.5*t

Step-by-step explanation:

Given:

The weight gain of the baby is 1.5 pounds per month.

After 4 months, baby's weight = 16 pounds

Let us the say the weight of the baby when it was born be x.

Then:

x + 1.5*(4) = 16

x = 10

Then weight of the baby as a function of number of months(t) will be=

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3 years ago
An electrician charges $15 plus $11 per hour. Another electrician charges $10 plus $15 per hour. Which of the systems of equatio
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3 years ago
5. (05.03 LC) What is the simplified form of the quantity of x plus 5, all over the quantity of 3x plus 4 + the quantity of x pl
earnstyle [38]

Answer:

B. \frac{4x^{2}+24x+31}{3x^{2}+13x+12}

Step-by-step explanation:

We have been given a rational expression \frac{(x+5)}{(3x+4)}+\frac{(x+4)}{(x+3)} and we are asked to simplify our rational expression.

We can see that our denominators are not equal. Since the two denominators do not share any common factors, the common denominator is simply the product of these two denominators.      

To keep the value of expression same we will multiply the same quantity with numerators and denominators.

\frac{(x+5)(x+3)}{(3x+4)(x+3)}+\frac{(x+4)(3x+4)}{(x+3)(3x+4)}  

Now let us simplify our expression using FOIL.  

\frac{x^{2}+3x+5x+15}{3x^{2}+9x+4x+12}+\frac{3x^2+4x+12x+16}{3x^{2}+4x+9x+12}

\frac{x^{2}+8x+15}{3x^{2}+13x+12}+\frac{3x^2+16x+16}{3x^{2}+13x+12}    

Now we have same denominators, so we can add our numerators.

\frac{x^{2}+8x+15+3x^2+16x+16}{3x^{2}+13x+12}    

Now let us combine like terms.

\frac{(1+3)x^{2}+(8+16)x+15+16}{3x^{2}+13x+12}  

\frac{4x^{2}+24x+31}{3x^{2}+13x+12}  

Therefore, the simplest form of our given rational expression will be \frac{4x^{2}+24x+31}{3x^{2}+13x+12}  and option B is the correct choice.

8 0
3 years ago
An 18-meter-tall cylindrical tank with a 4-meter radius holds water and is half full. Find the work (in mega-joules) needed to p
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Answer:

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W = 226290 x 9.8 x 9

W = 19958778Joules

W= 19.958778MegaJoules

Step-by-step explanation:

Work to full the tank is

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m is the mass of the water.

But density = mass/volume, where volume is the volume of the complete the remaining half full of water to fill the cylindrical tank.

mass = density x volume.

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Volume to fill the cylinder = (πr2h)/2.(half of total volume)

Volume = (22x4x4x9)/(7x2). Height used is 18/2 = 9m

Volume = 226.29m3.

Mass = density x volume= 1000 x 226.29 = 226290kg

Therefore, the work is

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Answer:

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