Question

a)express x^2+12x+11 in the form (x+p)^2+q b)A curve has equation y=x^2+12x+11. What are the co-ordinates of the turning point of the curve

Answer 1

a) (x+6)^2-25

b) (-6, -25)

Step-by-step explanation:

Perfect square trinomial! If you have 12x, divide by two and get 6, so we have (x+6)^2+q. Then solve for q. You get q as -25.

For b, we just take the vertex from vertex form. We get x+6=0 so x=-6, and q = -25, so the answer is (-6, -25).

Hope that helped,

-sirswagger21