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erik [133]
3 years ago
14

Which of the following angles has a measure that is less than 90 degrees?

Mathematics
2 answers:
Anastasy [175]3 years ago
5 0

Acute is the correct answer.

DIA [1.3K]3 years ago
4 0

obtuse is 91 degrees and up

right is exactly 90 degrees

 and acute is below 90 degrees

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What is the least common denominator of the rational expressions below? 4/x^2-7x + 1/x^2-4x-21
AleksAgata [21]

Answer:

x-7

Step-by-step explanation:

1. Find the GCF of x^2-7x (which is x) and factor x^2-4x-21

2. Multiply 1/(x-7)(x+) by x and 4/x(x-7) by (x+3) to get (x-7) as both denominators

3 0
2 years ago
How Do U write 310,763,136 in word from
pav-90 [236]
Three hundred ten million seven hundred sixty three thousand one hundred thirty six.

you never say 'and' when verbally saying a number because in math it implies a decimal is in place.
8 0
3 years ago
Read 2 more answers
What is 4,130,304 in scientific notation?
kakasveta [241]
4.130304x10^6= 4,130,304
7 0
3 years ago
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Use Simpson's Rule with n = 10 to estimate the arc length of the curve. Compare your answer with the value of the integral produ
SOVA2 [1]

y=\ln(6+x^3)\implies y'=\dfrac{3x^2}{6+x^3}

The arc length of the curve is

\displaystyle\int_0^5\sqrt{1+\frac{9x^4}{(6+x^3)^2}}\,\mathrm dx

which has a value of about 5.99086.

Let f(x)=\sqrt{1+\frac{9x^4}{(6+x^3)^2}}. Split up the interval of integration into 10 subintervals,

[0, 1/2], [1/2, 1], [1, 3/2], ..., [9/2, 5]

The left and right endpoints are given respectively by the sequences,

\ell_i=\dfrac{i-1}2

r_i=\dfrac i2

with 1\le i\le10.

These subintervals have midpoints given by

m_i=\dfrac{\ell_i+r_i}2=\dfrac{2i-1}4

Over each subinterval, we approximate f(x) with the quadratic polynomial

p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m_i)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}

so that the integral we want to find can be estimated as

\displaystyle\sum_{i=1}^{10}\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx

It turns out that

\displaystyle\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx=\frac{f(\ell_i)+4f(m_i)+f(r_i)}6

so that the arc length is approximately

\displaystyle\sum_{i=1}^{10}\frac{f(\ell_i)+4f(m_i)+f(r_i)}6\approx5.99086

5 0
3 years ago
3x^3-24x^2 factor completley
svetoff [14.1K]
3x^3-24x^2=> this is the expression, find what they have in common: 3 and x^2
3x^2(x-8)=> so we took out 3x^2

I hope this helps you:)!
7 0
3 years ago
Read 2 more answers
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