Question

Identify all factors of the expression 〖4x〗^2+17x-15.

Answer 1

The factors of given expression are: -5 and 3/4

Step-by-step explanation:

Given equation is:

$4x^2+17x-15$

Making pairs for the mid-term 17x by factoring the product of co-efficient of 4x^2 and 15

$4x^2+20x-3x-15$

$= 4x(x+5) - 3(x+5)$

$=(4x-3)(x+5)$

Now

$4x-3 = 0\\4x = 3\\x = \frac{3}{4}$

$x+5 = 0\\x = -5$

Hence,

The factors of given expression are: -5 and 3/4

Keywords: Quadratic equation, factors

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