Given:
4log1/2^w (2log1/2^u-3log1/2^v)
Req'd:
Single logarithm = ?
Sol'n:
First remove the parenthesis,
4 log 1/2 (w) + 2 log 1/2 (u) - 3 log 1/2 (v)
Simplify each term,
Simplify the 4 log 1/2 (w) by moving the constant 4 inside the logarithm;
Simplify the 2 log 1/2 (u) by moving the constant 2 inside the logarithm;
Simplify the -3 log 1/2 (v) by moving the constant -3 inside the logarithm:
log 1/2 (w^4) + 2 log 1/2 (u) - 3 log 1/2 (v)
log 1/2 (w^4) + log 1/2 (u^2) - log 1/2 (v^3)
We have to use the product property of logarithms which is log of b (x) + log of b (y) = log of b (xy):
Thus,
Log of 1/2 (w^4 u^2) - log of 1/2 (v^3)
then use the quotient property of logarithms which is log of b (x) - log of b (y) = log of b (x/y)
Therefore,
log of 1/2 (w^4 u^2 / v^3)
and for the final step and answer, reorder or rearrange w^4 and u^2:
log of 1/2 (u^2 w^4 / v^3)
Answer:
First: 12 feet
Second: 11 feet
Third: 14 feet
Step-by-step explanation:
Let the second side of the traingle be x
First side of the triangle= x+1
Third side of the triangle= x+3
x+x+1+x+3 = 37
3x+4 = 37
3x = 37-4
3x = 33
x = 11
First side of the triangle= (11)+1
= 12
Second side of the triangle= 11
Third side of the triangle= (11)+3
= 14
Answer:
- 10 - (-20 + 5)
Step-by-step explanation:
- 10 - (-20 + 5)
- 10 - (-15) = -10 + 15
-10 + 15 = 5
have a nice day and mark me brainliest! :)
9/5
the distance is 9 over, and 5 up.
