Area of Triangle:
A = 1/2 bh = 1/2 (5)(12) = 30 m^2
Area of semicircle:
A = 1/2 π r^2 = 1/2 π 6^2 = 18<span>π m^2
Area of figure = </span>Area of semicircle + Area of Triangle
Area of figure = 18π + 30 m^2
Answer is C.
18π + 30 m^2
<em>Heyo! ;D</em>
After evaluating the given expression, the result would be <em>14 - x.</em>
<em></em>
<em></em>
Hope this helped you! If so, please lmk! Tysm and good luck!
9514 1404 393
Answer:
Step-by-step explanation:
You know the linear pair z° and 105° are supplementary angles, so ...
z = 180 -105 = 75
The other base angle of the isosceles triangle has the same measure, 75°. __
Then x can be found either from the sum of interior angles of the triangle, or from the relation of 105° to the "remote interior angles". The first relation gives ...
75° +75° +x° = 180° ⇒ x = 180 -150 = 30
The second relation gives ...
75° +x° = 105° ⇒ x = 105 -75 = 30
__
y° is supplementary to the left-side base angle, so is ...
y = 180 -75 = 105
Of course, you could also figure y from the symmetry of the figure.
The values of x, y, z are 30, 105, 75, respectively.
Answer:
44fps, or 44:1
Step-by-step explanation:
it is already a unit rate
Answer:
i dont know it either im in 6th grade...
Step-by-step explanation:
