Yes you can because you just can
To write an equation in standard form, move each term to the left side of the equation and simplify.
ax2+bx+c = 0ax2+bx+c = 0
Move all the expressions to the left side of the equation.
−17−8x2−4x+3x2 = 0-17-8x2-4x+3x2 = 0
Add −8x2-8x2 and 3x23x2.
−17−5x2−4x = 0-17-5x2-4x = 0
Reorder the polynomial.
5x2+4x+17 = 0
Step-by-step explanation:
I hope this helped-
Answer:
C = 24
Step-by-step explanation:
(x - 6)² - 12 = x² - 12x + c
(x - 6) (x - 6) -12 = x² - 12x + c
x(x - 6) - 6(x - 6) - 12 = x² - 12x + c
x² - 6x -6x + 36 - 12 = x² - 12x + c
x² - 12x +36 - 12 = x² - 12x + c
x² - 12x + 24 = x² - 12x + c
24 = c
Answer:
<h2>
3,654 different ways.</h2>
Step-by-step explanation:
If there are 30 students in a class with natasha in the class and natasha is to select four leaders in the class of which she is already part of the selection, this means there are 3 more leaders needed to be selected among the remaining 29 students (natasha being an exception).
Using the combination formula since we are selecting and combination has to do with selection, If r object are to selected from n pool of objects, this can be done in nCr number of ways.
nCr = n!/(n-r)!r!
Sinca natasha is to select 3 more leaders from the remaining 29students, this can be done in 29C3 number of ways.
29C3 = 29!/(29-3)!3!
29C3 = 29!/(26!)!3!
29C3 = 29*28*27*26!/26!3*2
29C3 = 29*28*27/6
29C3 = 3,654 different ways.
This means that there are 3,654 different ways to select the 4 leaders so that natasha is one of the leaders
Answer:
X2+4<10
Step-by-step explanation:
