Answer:
0.375 moles of CaCO₃ are required
Explanation:
Given data:
Number of moles of sulfamic acid = 0.75 mol
Number of moles of calcium carbonate required = ?
Solution:
Chemical equation:
2H₃NSO₃ + CaCO₃ → Ca(SO₃NH₂)₂ + CO₂ + H₂O
Now we will compare the moles of H₃NSO₃ and CaCO₃ .
H₃NSO₃ : CaCO₃
2 : 1
0.75 : 1/2×0.75 = 0.375 mol
Thus, 0.375 moles of CaCO₃ are required.
Answer: any non-living thing
Explanation: abiotic means non-living
Leftover: approximately 11.73 g of sulfuric acid.
<h3>Explanation</h3>
Which reactant is <em>in excess</em>?
The theoretical yield of water from Al(OH)₃ is lower than that from H₂SO₄. As a result,
- Al(OH)₃ is the limiting reactant.
- H₂SO₄ is in excess.
How many <em>moles</em> of H₂SO₄ is consumed?
Balanced equation:
2 Al(OH)₃ + 3 H₂SO₄ → Al₂(SO₄)₃ + 6 H₂O
Each mole of Al(OH)₃ corresponds to 3/2 moles of H₂SO4. The formula mass of Al(OH)₃ is 78.003 g/mol. There are 15 / 78.003 = 0.19230 moles of Al(OH)₃ in the five grams of Al(OH)₃ available. Al(OH)₃ is in excess, meaning that all 0.19230 moles will be consumed. Accordingly, 0.19230 × 3/2 = 0.28845 moles of H₂SO₄ will be consumed.
How many <em>grams</em> of H₂SO₄ is consumed?
The molar mass of H₂SO₄ is 98.076 g.mol. The mass of 0.28845 moles of H₂SO₄ is 0.28845 × 98.076 = 28.289 g.
How many <em>grams</em> of H₂SO₄ is in excess?
40 grams of sulfuric acid H₂SO₄ is available. 28.289 grams is consumed. The remaining 40 - 28.289 = 11.711 g is in excess. That's closest to the first option: 11.73 g of sulfuric acid.
Ice has the lowest energy; liquid water has “medium” energy; and water vapor has the highest energy.
Molarity can be defined as the moles of solute in a liter of solution. The molarity of the salt solution is 
.
<h3>What is the relation between moles and volume?</h3>
The moles are the mass of substance with respect to the molar mass. The moles and volume relationship can be expressed in terms of molarity.
The molarity can be expressed as:
The given solution has,
- Moles of salt =
- The volume of solution =
L.
Substituting the values for molarity as:
The molarity of the solution is . Thus, option C is correct.
Learn more about molarity, here:
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