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3 years ago

Limescale removers contain sulfamic acid, H3NSO3, which reacts with minerals in hard water

Chemistry

1 answer:

I am Lyosha [343]3 years ago

4 0

Answer:

0.375 moles of CaCO₃ are required

Explanation:

Given data:

Number of moles of sulfamic acid = 0.75 mol

Number of moles of calcium carbonate required = ?

Solution:

Chemical equation:

2H₃NSO₃ + CaCO₃ → Ca(SO₃NH₂)₂ + CO₂ + H₂O

Now we will compare the moles of H₃NSO₃ and CaCO₃ .

H₃NSO₃ : CaCO₃

2 : 1

0.75 : 1/2×0.75 = 0.375 mol

Thus, 0.375 moles of CaCO₃ are required.

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Find the % composition for each element in Zinc Chlorate

Archy [21]

Answer:

chlorine ~ 30%

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oxygen ~ 41%

Explanation:

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3 years ago

Should carbon dioxide be considered to be a pullutant

Kipish [7]

Answer:

yes, as it helps to increase global warming and it's main cause is deforestation

Explanation:

as carbon dioxide is a greenhouse gas. It helps to increase global warming

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3 years ago

Th e enzyme-catalyzed conversion of a substrate at 25°C has a Michaelis constant of 0.045 mol dm−3. Th e rate of the reaction is

Elis [28]

Answer:

$1.620\times 10^{-3} mol/dm^3 s$ is the maximum velocity of this reaction.

Explanation:

Michaelis–Menten 's equation:

$v=V_{max}\times \frac{[S]}{K_m+[S]}=k_{cat}[E_o]\times \frac{[S]}{K_m+[S]}$

$V_{max}=k_{cat}[E_o]$

v = rate of formation of products =

[S] = Concatenation of substrate

$[K_m]$ = Michaelis constant

$V_{max}$ = Maximum rate achieved

$k_{cat}$ = Catalytic rate of the system

$[E_o]$ = Initial concentration of enzyme

We have :

$K_m=0.045 mol/dm^3$

$v=1.15 mmol/dm^3 s=1.15\times 10^{-3} mol/dm^3 s$

$[S]=0.110 mol/dm^3$

$v=V_{max}\times \frac{[S]}{K_m+[S]}$

$1.15\times 10^{-3} mol/dm^3 s=V_{max}\times \frac{0.110 mol/dm^3}{[(0.045 mol/dm^3)+(0.110 mol/dm^3)]}$

$V_{max}=\frac{1.15\times 10^{-3} mol/dm^3 s\times [(0.045 mol/dm^3)+(0.110 mol/dm^3)]}{0.110 mol/dm^3}=1.620\times 10^{-3} mol/dm^3 s$

$1.620\times 10^{-3} mol/dm^3 s$ is the maximum velocity of this reaction.

8 0

3 years ago

A 30ml sample of a liquid has a mass of 50 grams. What is the density of the liquid?

mash [69]

Answer:

<h2>Density = 1.67 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

$Density = \frac{mass}{volume}$

From the question

mass = 50 g

volume = 30 mL

Substitute the values into the above formula and solve for the density

That's

$Density = \frac{50}{30} \\ = \frac{5}{3} \\ = 1.66666...$

Wr have the final answer as

<h3>Density = 1.67 g/mL</h3>

Hope this helps you

5 0

3 years ago

The decomposition of N2O5 in solution in carbon tetrachloride proceeds via the reaction 2 N2O5(soln) → 4 NO2(soln) + O2(soln) Th

Fantom [35]

<u>Answer:</u> The amount remained after 151 seconds are 0.041 moles

<u>Explanation:</u>

All the radioactive reactions follows first order kinetics.

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$

where,

k = rate constant = $4.82\times 10^{-3}s^{-1}$

t = time taken for decay process = 151 sec

$[A_o]$ = initial amount of the reactant = 0.085 moles

[A] = amount left after decay process = ?

Putting values in above equation, we get:

$4.82\times 10^{-3}=\frac{2.303}{151}\log\frac{0.085}{[A]}$

$[A]=0.041moles$

Hence, the amount remained after 151 seconds are 0.041 moles

7 0

3 years ago