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Hoochie [10]
3 years ago
6

Limescale removers contain sulfamic acid, H3NSO3, which reacts with minerals in hard water

Chemistry
1 answer:
I am Lyosha [343]3 years ago
4 0

Answer:

0.375 moles of CaCO₃ are required

Explanation:

Given data:

Number of moles of sulfamic acid = 0.75 mol

Number of moles of calcium carbonate required = ?

Solution:

Chemical equation:

2H₃NSO₃ + CaCO₃     →        Ca(SO₃NH₂)₂ + CO₂ + H₂O

Now we will compare the moles of H₃NSO₃  and CaCO₃ .

                H₃NSO₃           :            CaCO₃  

                     2                 :             1

                   0.75              :           1/2×0.75 = 0.375 mol

Thus, 0.375 moles of CaCO₃ are required.

 

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Answer:

A. percentage mass of iron = 5.17%

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B. (Iron + sand + water) -------> ( iron + sand) ------> sand

C. The step of separation of iron and sand

Explanation:

A. Percentage mass of the mixtures:

Total mass of mixture = (15.0 + 25.0 + 250.0) g =290.0 g

percentage mass of iron = 15/290 * 100% = 5.17%

percentage mass of sand = 25/290 * 100% = 8.62%

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B. Flow chart of separation procedure

(Iron + sand + water) -------> separation by filtration using filter paper and funnel to remove water --------> ( iron + sand) -----------> separation using magnet to remove iron ------> sand

C. The step of separation of iron and sand by magnetization of iron will have the highest amount of error because during the process, some iron particles may not readily be attracted to the magnet as they may have become interlaced in-between sand grains. Also, some sand particle may also be attracted to the magnet as they are are borne on iron particles.

5 0
3 years ago
Density is d= m/vol. If a material has a mass of 65.5 g and a volume of 32.5 ml, it has a density of
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Using the given formula, the density of the material is 2.015 g/mL

<h3>Calculating Density </h3>

From the question, we are to determine the density of the material

From the given formula

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And from the given information,

Mass = 65.5 g

and volume = 32.5 mL

Putting the parameters into the equation,

Density = 65.5/32.5

Density = 2.015 g/mL

Hence, the density of the material is 2.015 g/mL.

Learn more on Calculating density here: brainly.com/question/24772401

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3 years ago
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