Answer:
Options (1), (2), (3) and (7)
Step-by-step explanation:
Given expression is
.
Now we will solve this expression with the help of law of exponents.
![\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B8%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%5Ctimes%203%7D%20%7D%7B3%5Ctimes2%5E%7B%5Cfrac%7B1%7D%7B9%7D%7D%7D%3D%5Cfrac%7B%5Csqrt%5B3%5D%7B%282%5E3%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%5Ctimes%203%7D%20%7D%7B3%5Ctimes2%5E%7B%5Cfrac%7B1%7D%7B9%7D%7D%7D)
![=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5Csqrt%5B3%5D%7B2%5Ctimes%203%7D%20%7D%7B3%5Ctimes2%5E%7B%5Cfrac%7B1%7D%7B9%7D%7D%7D)




[Option 2]
[Option 1]
![2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B2%7D%7B9%7D%7D%5Ctimes%203%5E%7B-%5Cfrac%7B2%7D%7B3%7D%20%7D%3D%28%5Csqrt%5B9%5D%7B2%7D%29%5E2%5Ctimes%20%28%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B3%7D%20%7D%20%29%5E2)

[Option 3]

[Option 7]
Therefore, Options (1), (2), (3) and (7) are the correct options.
Let x be the unknown number.
7x + 668 < 2000 => 7x plus 668 is less than 2000
where:
7x => x represents the number of cans to be collected in 7 days
668 is the number of cans already collected.
2000 is the target number of cans.
7x + 668 < 2000
<u> - 668 -668</u>
7x < 1332
<u>÷7 ÷7</u>
x < 190.30
or
x < 190
To check:
7x + 668 < 2000
7(190) + 668 < 2000
1330 + 668 < 2000
1998 < 2000
81 servings. I found this by making a ratio:
24 c 108 c
------- = -------
18 ser x
I then cross multiplied to get the equation: 24x=1,944. I solved this equation to find x, the number of servings in 108 cups, which was 81.
I remember doing this back in elementary school. I had a hard time with it too!
The answer is the last one. Just plug 1,2,3,4 in for n.