Answer:
(a) The inequality for the number of items, x, produced by the labor, is given as follows;
250 ≤ x ≤ 600
(b) The inequality for the cost, C is $1,000 ≤ C ≤ $3,000
Step-by-step explanation:
The total time available for production = 1000 hours per week
The time it takes to produce an item on line A = 1 hour
The time it takes to produce an item on line B = 4 hour
Therefore, with both lines working simultaneously, the time it takes to produce 5 items = 4 hours
The number of items produced per the weekly labor = 1000/4 × 5 = 1,250 items
The minimum number of items that can be produced is when only line B is working which produces 1 item per 4 hours, with the weekly number of items = 1000/4 × 1 = 250 items
Therefore, the number of items, x, produced per week with the available labor is given as follows;
250 ≤ x ≤ 1250
Which is revised to 250 ≤ x ≤ 600 as shown in the following answer
(b) The cost of producing a single item on line A = $5
The cost of producing a single item on line B = $4
The total available amount for operating cost = $3,000
Therefore, given that we can have either one item each from lines A and B with a total possible item
When the minimum number of possible items is produced by line B, we have;
Cost = 250 × 4 = $1,000
When the maximum number of items possible, 1,250, is produced, whereby we have 250 items produced from line B and 1,000 items produced from line A, the total cost becomes;
Total cost = 250 × 4 + 1000 × 5 = 6,000
Whereby available weekly outlay = $3000, the maximum that can be produced from line A alone is therefore;
$3,000/$5 = 600 items = The maximum number of items that can be produced
The inequality for the cost, C, becomes;
$1,000 ≤ C ≤ $3,000
The time to produce the maximum 600 items on line A alone is given as follows;
1 hour/item × 600 items = 600 hours
The inequality for the number of items, x, produced by the labor, is therefore, given as follows;
250 ≤ x ≤ 600
