Answer:
The pair of numbers that has a product of ac and a sum of b = (+2, +8)
The factored form of the trinomial = (x+2) (x+8)
Step-by-step explanation:
ax² + bx + c = 0
This is in the form of a trinomial algebraic expression
Given trinomial: = ax² + 10x + 16
Where a = 1, b= 10, c= 16
To find the pair of numbers that has a product of ac and a sum of b, we would solve the equation.
Using factorisation method:
ac = a×c = 1×16 = 16
Let's find the factors of 16 whose sum gives +10 and product gives +16
Factors of 16 = 1, 2, 8, 16
+2 + +8 = +10
+2 × +8 = +16
The factors are +2 and +8
The pair of numbers that has a product of ac and a sum of b = (+2, +8)
x² + 10x + 16 = x + 2x + 8x + 16
x² + 10x + 16 = x(x+2) + 8(x+2)
= (x+2) (x+8)
The factored form of the trinomial = (x+2) (x+8)
