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3 years ago

24 in 70 in What is the length of the hypotenuse?

Mathematics

1 answer:

neonofarm [45]3 years ago

3 0

Answer:74inch

Step-by-step explanation:

Assuming this is a right triangle you do pythogreom theorm and get 74 inches

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Multiply the polynomials: (x + 3)(x2 – 5x + 12)

LekaFEV [45]

Answer:

x³ - 2x² - 3x + 36

Step-by-step explanation:

(x + 3)(x² - 5x + 12)

Each term in the second factor is multiplied by each term in the first factor , that is

x(x² - 5x + 12) + 3(x² - 5x + 12) ← distribute parenthesis

= x³ - 5x² + 12x + 3x² - 15x + 36 ← collect like terms

= x³ - 2x² - 3x + 36

3 0

3 years ago

Read 2 more answers

HELP PLEASE 100 POINTS! Review the diagram below. Apply the properties of angles to solve for the missing angles. Angle x is ___

Arisa [49]

Step-by-step explanation:

<y+60+58=180 (angle sum property)

<y+118=180

<y=180-118=62

<ACB+<ACD=180(degree of a line )

58+x=180

x=122

(btw u cant get a 100 points by answering one question)

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3 years ago

Write the equation of the line passing through the point (2,-1) with a slope of -3

Alexxandr [17]

Y= 2x-3 i think, but i may be wrong

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3 years ago

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if Kevin processed 135 orders and Michael did 90 orders what percentage did Kevin do more than Michael

vagabundo [1.1K]

90/135 = 0.666666667
0.666 x 100 = 66.6 %

7 0

3 years ago

If a > b > c > d, then which is larger, a+c or b+d ? Can we tell from a > b > c > d which of a+d and b+c is la

victus00 [196]

Answer:

1. a+c is larger than b+d

2. No way to tell whether a+d or b+c is larger.

Step-by-step explanation:

1. Which is larger, a+c or b+d?

Let a, b, c, and d be any numbers such that $a > b > c > d$ .

Specifically, note that $a > b$ , and subtracting b from both sides of the inequality, observe that $a-b > 0$ .

Similarly, $c > d$ , and subtracting d from both sides of the inequality, observe that $c-d > 0$ .

From this, add "a-b" (a positive number, as proven above) to both sides of the inequality.

$(a-b)+(c-d) > (a-b)+0$

Addition by zero (the additive identity) doesn't change anything, so the right side remains "a-b"...

$(a-b)+(c-d) > a-b$

... and "a-b" is positive...

$(a-b)+(c-d) > a-b > 0$

... so, by the transitive property of inequality...

$(a-b)+(c-d) > 0$

Recall that subtraction is addition by a negative number...
$a+(-b)+c+(-d) > 0$

...and that addition is associative and commutative, so things can be added in any order, so the middle two terms on the left side can be rearranged...

$a+c+(-b)+(-d) > 0$

Adding b + d to both sides of the inequality

$(a+c+(-b)+(-d))+(b+d) > 0+(b+d)$

... and simplifying

$a+c > b+d$

So, a+c is larger than b+d.

2. Which is larger, a+d or b+c?

Consider the following two examples:

Example 1

Suppose a=10; b=3; c=2; d=1.

Note that $a > b > c > d$ ( $10 > 3 > 2 > 1$ ) and, also observe that $a+d=(10)+(1)=11$ , and $b+c=(3)+(2)=5$ , so a+d is larger than b+c.

Example 2

However, suppose a=10; b=9; c=8; d=1.

Note that $a > b > c > d$ ( $10 > 9 > 8 > 1$ ) but that $a+d=(10)+(1)=11$ , and $b+c=(9)+(8)=17$ , so a+d is smaller than b+c.

So, in one example, a+d is bigger, and in the other, a+d is smaller. Therefore, there is no way to tell which of a+d or b+c is larger from only the given information.

5 0

2 years ago