A^2+b^2=c^2
(2sqrt3)^2+b^2=16
12+b^2=16
solve for b
b=2
Now triangle area is A=1/2 bh
so
A=(1/2)(2)(2sqrt3)
A=2sqrt3
Answer: <em>I think the answer is 5</em>
Step-by-step explanation:
Answer:
q=10
Step-by-step explanation:
-10+10q=9q
-10=-q
q=10
Answer:
The time taken for the projectile to reach the given height is 1.2 s.
Step-by-step explanation:
Given;
height of travel, h = 25 ft
initial velocity of the projectile, u = 15 ft/s
The time taken for the projectile to travel a height of 25 ft is given by the following kinematic equation;
h = ut + ¹/₂gt²
25 = 15t + ¹/₂(9.8)t²
25 = 15t + 4.9t²
4.9t² + 15t - 25 = 0
solving the quadratic equation, we will have the following solution of t;
t = 1.2 s
Therefore, the time taken for the projectile to reach the given height is 1.2 s.
