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schepotkina [342]
3 years ago
8

If x^2 - 16 > 0, which of the following must be true?

Mathematics
1 answer:
zimovet [89]3 years ago
5 0
The left hand side of the equation is a difference of two squares and may be factored out as follows,
                              (x - 4)(x + 4) > 0
They may be individually taken as,
                                     x - 4 > 0    ; x > 4
                                     x + 4 > 0   ; x < -4
Thus, the answer to this item is letter A. 
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a=-  \frac{ x^{2}-  \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2} ,-  \frac{ x^{2}+  \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2}

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b= \frac{12}{x}+ \frac{72}{ x^{2} }-2+2a- \frac{4a}{x}+ \frac{ a^{2} }{x}- \frac{2a^{z} }{ x^{2} }

Hopefully i helped ^.^ Mark brainly if possible 
 

7 0
3 years ago
Giving brainly if both are done and correct​
pshichka [43]

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A.) -84

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Step-by-step explanation:

I hope I helped! ^-^

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