Answer:
- b. y = 2/3x +5
- c. y = -3 or -1/2
Step-by-step explanation:
b. The particualar steps for solving a linear equation such as this may vary from one equation to another. In general, you want to put all the y-terms on one side of the equal sign and everything else on the other side. Here's how we'll do that in this case.
Use the distributive property to eliminate parentheses.
... 6x -3y +12 = 4x -3
Find the unwanted terms on the side of the equation where y is, then add their opposite. In this case, we're adding -(6x+12)
... -3y = (4x -3) -(6x +12) = -2x -15
Divide by the coefficient of y.
... y = -2x/(-3) -15/(-3)
... y = 2/3x +5
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c. This is a 2nd-degree (quadratic) equation with y as its only variable. The factor (2y+1) appears in both terms so we can use the distributive property to factor it out. Then the equation becomes ...
... (y +3)(2y +1) = 0
The zero product rule tells us this product will be zero only when one or the other of the factors is zero. This fact helps us find the values of y that are the solution to the equation.
For y+3 = 0:
... y + 3 = 0
... y = -3 . . . . . . add -3 to both sides of the equation
For 2y +1 = 0:
... 2y +1 = 0
... y +1/2 = 0 . . . . divide by 2
... y = -1/2 . . . . . . add -1/2
The solutions are y = -3 or y = -1/2.
Answer:
Step-by-step explanation:
STEP 1: Subtract 11x from 7x.
STEP 2: Subtract 10 from 12.
Answer:
the answer is 72,792
Step-by-step explanation:
just subtract 72,792-72
A) For this problem, we will need to use a normal calculation, in that we find the z-score and the area to the right using Table A.
z = (10 - 7.65) / 1.45
z = 1.62
area to the left for a z-score of 1.62 = 0.9474
area to the right for a z-score of 1.62 = 0.0526
The probability that a randomly selected ornament will cost more than $10 is 0.0526 or 5.26%.
B) For this problem, we will use the binomial probability formula since the problem is asking for the probability that exactly 3 ornaments cost over $10. There are two forms of this equation. One is <em>nCr x p^r x q^n-r</em> and the other is <em>(n r) x p^r x (1 - p)^n-r</em>. I will show both formulas below.
8C3 x 0.0526^3 x 0.9474^5
(8 3) x 0.0526^3 x 0.9474^5
With both equations, the answer is the same. Whichever you are more familiar or comfortable with is the one I would recommend you use.
The probability that exactly 3 of the 8 ornaments cost over $10 is 0.00622 or 0.622%.
Hope this helps!! :)
