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Y_Kistochka [10]
3 years ago
5

James used 3 1/4 cups of flour in a cookie recipe and 2 1/2 cups of flour in a bread recipe. How many cups of flour use combined

in both recipes
Mathematics
2 answers:
irina [24]3 years ago
4 0
Answer:
5 3/4

Step by step explanation:
Find a common denominator in this case is 4 so instead of adding 2 1/2 to 3 1/4 it’s going to be 3 1/4 + 2 2/4 which gets you 5 3/4
scoray [572]3 years ago
3 0

Answer: he used 5 3/4 cups of flour.

Step-by-step explanation:

1/2 of 4 is 2; thus 2/4 equals 1/2.

Substitute 2 1/2 to 2 2/4 and add.

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143 is composite. To be prime it has to have only 2 divisors i.e it's self and one but since it has 4 divisors ( 143, 1, 11 and 13) it is composite.
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Newton's law of cooling is:
Mnenie [13.5K]

Answer:

t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr

So it would takes approximately 6.9 hours to reach 32 F.

Step-by-step explanation:

For this case we have the following differential equationÑ

\frac{du}{dt}= -k (u-T)

We can reorder the expression like this:

\frac{du}{u-T} = -k dt

We can use the substitution w = u-T and dw =du so then we have:

\frac{dw}{w} =-k dt

IF we integrate both sides we got:

ln |w| = -kt +C

If we apply exponential in both sides we got:

w = e^{-kt} *e^c

And if we replace w = u-T we got:

u(t)= T + C_1 e^{-kt}

We can also express the solution in the following terms:

u(t) = (T_i -T_{amb}) e^{kt} +T_{amb}

For this case we know that k =-0.15 hr since w ehave a cooloing, T_{i}= 70 F, T_{amb}=11F, we have this model:

u(t) = (70-11) e^{-0.15t} +11

And if we want that the temperature would be 32F we can solve for t like this:

32 = 59 e^{-0.15 t} +11

21=59 e^{-0.15 t}

\frac{21}{59} = e^{-0.15 t}

If we apply natural logs on both sides we got:

ln (\frac{21}{59}) =-0.15 t

t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr

So it would takes approximately 6.9 hours to reach 32 F.

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Yeah sure! Just make sure to post them haha :)
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Answer:

1/24

Step-by-step explanation:

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Answer:

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