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Mathematics

1 answer:

Ganezh [65]3 years ago

8 0

The correct answer is B. You know this because you are just adding like terms or in this case the same exponents.

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Six classrooms lost electricity this morning for 47 minutes. Determine the percent of an hour that the classrooms were without e

meriva

They were without electricity for 47 minutes.....determine the percent of an hr....so 1 hr = 60 minutes.....so they were out 47 out of 60 minutes...
47/60 = 0.783 = 78.3%.....so just type in 78.3 because ur not supposed to include the percent sign

8 0

3 years ago

jeka57 [31]

Answer:

Step-by-step explanation:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\(-5,1)\quad\implies\quad x_1=-5\,,\ \ y_1=1\\\\(-1,4)\quad\implies\quad x_2=-1\,,\ \ y_2=4\\\\d=\sqrt{(-1+5)^2+(4-1)^2}= \sqrt{4^2+3^2}=\sqrt{16+9}=\sqrt{25}=5$

4 0

3 years ago

Complete the statements to explain how to factor x2 x â€" 12 using algebra tiles. represent the trinomial using 1 positive x2-ti

olga55 [171]

Answer:

1 positive x-tile, 12 negative x-tiles, three, and (x -3) (x + 4) are the answers

Step-by-step explanation:

worked on edge 2022

5 0

1 year ago

Read 2 more answers

Suppose that the quarterly sales levels among health care information systems companies are approximately normally distributed w

cupoosta [38]

Answer:

The cutoff sales level is 10.7436 millions of dollars

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 12, \sigma = 1.2$