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KIM [24]
2 years ago
15

Given f(x)=x-7 and h(x)=2x+3 write the rule for f(h(x))​

Mathematics
1 answer:
cestrela7 [59]2 years ago
6 0

Step-by-step explanation:

f(x)=x-7&h(x)=2x+3 then fohx)=2x-4

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The value 5 is an upper bound for the zeros of the function shown below.
Mice21 [21]

Answer:

The given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18  will be true.

Step-by-step explanation:

Given

f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18

We know the rational zeros theorem such as:

if x=c is a zero of the function f(x),

then f(c) = 0.

As the f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18 is a polynomial of degree 4, hence it can not have more than 4 real zeros.

Let us put certain values in the function,

f(5) = 448, f(4) = 126, f(3) = 0, f(2) = -20,

f(1) = 0, f(0) = 18, f(-1) = 16, f(-2) = 0, f(-3) = 0

From the above calculation results, we determined that 4 zeros as

x = -3, -2, 1, and 3.

Hence, we can check that

f(x) = (x+3)(x+2)(x-1)(x-3)

Observe that,

for x > 3, f(x) increases rapidly, so there will be no zeros for x>3.

Therefore, the given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18  will be true.

5 0
3 years ago
Y=2x+7<br> y−2x=7<br> how many solutions does it have
quester [9]

Answer: Many solutions!

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Write an equation for each line
Semmy [17]
There is no information here, could you add more. There are no lines for us to help you with so this makes it confusing for others, add more information for us to be able to help.
4 0
3 years ago
In the figure below, AB=AE, AC=AD and AP is perpendicular to BE. Prove that BC=DE.
NISA [10]

Step-by-step explanation:

1) In the figure, as AB is equal to AE, ABE is an equilateral triangle.

As AP is perpendicular to BE

=> AP is the height of the triangle ABE.

In an equilateral triangle, the median and the height is the same, so that AP is also the median of the triangle.

=> P is the midpoint of BE

=> PE = PB

2) In the figure, as AC = AD, so that ACD is an equilateral triangle.

As AP is perpendicular to BE,  so that it is perpendicular to CD as well

=> AP is the height of the triangle ACD

In an equilateral triangle, the median and the height is the same, so that AP is also the median of the triangle ACD.

=> P is the midpoint of CD

=> PC = PD

We have:

+) PB = PE

+) PC = PD

=> PB - PC = PE - PD => BC = DE

5 0
3 years ago
Are these similar ?
Ksju [112]

Answer:

Yes, by S-A-S

Step-by-step explanation:

Angle M and Angle A are congruent, and the labeled sides are proportionate to each other so they are similar.

4 0
2 years ago
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