Answer:
112 m
Step-by-step explanation:
The area (A) of a square is
A = s² ( s is the length of side )
Here A = 784 , then
s² = 784 ( take the square root of both sides )
s = 
= 28
Then
perimeter = 4s = 4 × 28 = 112 m
Step-by-step explanation:
there is no diagram so I'm just going to guess this however
sin x = 6/9
sin x = 2/3
sin x = 0.67
x = sin inverse of 0.67
x = 42.1
Answer:
Other diagonal is 8 m
Step-by-step explanation:
area of rhombus = 72 m²
½ × diagonal 1 × diagonal 2 = 72
½ × 18 × d2 = 72
9 × d2 = 72
d2 = 72/9
d2 = 8
Answer:
SAS requires two congruent sides and the included angle be also congruent
Given is the picture are congruent triangles
<u>ΔACB ≅ ΔECD, because:</u>
- AC ≅ EC, given
- BC ≅ DC, given
- ∠ACB ≅ ∠ECD, vertical angles
<span><span>y = 2 + 2sec(2x)
The upper part of the range will be when the secant has the smallest
positive value up to infinity.
The smallest positive value of the secant is 1
So the minimum of the upper part of the range of
y = 2 + 2sec(2x) is 2 + 2(1) = 2 + 2 = 4
So the upper part of the range is [4, )
The lower part of the range will be from negative infinity
up to when the secant has the largest negative value.
The largest negative value of the secant is -1
So the maximum of the lower part of the range of
y = 2 + 2sec(2x) is 2 + 2(-1) = 2 - 2 = 0
So the lower part of the range is (, 0].
Therefore the range is (, 0] U [4, )
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