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denpristay [2]
1 year ago
5

Enter the correct answer in the box. If z>0, what is the quotient of 20 square root of z^6 • square root of 16x^7 in simplest

radical form? If necessary, rationalize the denominator
Mathematics
1 answer:
malfutka [58]1 year ago
4 0

The correct answer which represents the quotient of 20√z⁶ ÷ √16z⁷ in simplest radical form is; (5√z)/z.

<h3>What is the quotient of the expression in its simplest radical form?</h3>

The quotient given can be evaluated by means of the laws of indices as follows;

20√z⁶ ÷ √16z⁷

= 20√z⁶ ÷ 4√z⁷

= 5 √(z⁶/z⁷)

= 5 √z^(-1)

= 5 × z^(-1/2)

= 5/√z

Hence, by rationalisation; we have;

= (5√z)/z.

Read more on rationalisation;

brainly.com/question/27887772

#SPJ1

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Mariana [72]
The range is {-5, -4, 2}.

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Hope this helps!!!
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3 years ago
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6 0
3 years ago
All sides of quadrilateral ABCD are tangent to circle P.
VARVARA [1.3K]

Answer:

44.4 units

Step-by-step explanation:

Recall: 2 tangents drawn from an external point from a circle are congruent

Perimeter of the quadrilateral = AB + BC + CD + AD

AB = 3.1 + 8 = 11.1

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CD = 11.1 (given)

AD = 8 + 3.1 = 11.1

Perimeter = 11.1 + 11.1 + 11.1 + 11.1

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6 0
3 years ago
What is the final efficiency of Lily's car in kilometers per liter?
Elena-2011 [213]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
How long will it take for an object to fall from 15m?
Solnce55 [7]

The time taken by the object to fall from 15 m on the Mercury which has a gravity of 3.7 m/s² is 10.54 seconds.

<h3>What is kinematics?</h3>

It is the study of the motion of a body without considering mass. And the reason behind them is neglected.

The object is on Mercury and starts falling from rest.

As it is on Mercury there is no air resistance to account for.

Gravity on Mercury is 3.7 m/s².

Then the time taken by the object to fall from 15 m will be given as

\rm t = \sqrt{2gh}\\\\t = \sqrt{2\times 3.7\times 15}\\\\t = 10.5356 \approx 10.54  \ seconds

More about the kinematics link is given below.

brainly.com/question/25638908

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5 0
3 years ago
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