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Gemiola [76]
3 years ago
7

Help me, please!!!!!!!

Mathematics
1 answer:
navik [9.2K]3 years ago
8 0

9514 1404 393

Answer:

  2

Step-by-step explanation:

Alex has 10 money units. Annie has 5 money units. The ratio of amounts is ...

  Alex : Annie = 10 : 5 = 2 : 1

Alex has 2 times as much money as Annie.

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Emilio's teacher asks him to draw a triangle that contains a right angle. Two of the three sides of the triangle must have measu
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Answer:

2

Step-by-step explanation:

There would be 3 possible measurements for the 3rd side of the triangle because if you use the hypotenuese formula, you see C^2 = A^2 + B^2 so the two sides could be A and B, or they can be C and A / C and B but the C and __ would be the same for both A and B because they would be added the same way. (they would be equal)

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A)A random sample was used.

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If Mary walks 3 feet every 2 seconds, how many feet does she walk in an hour?
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6 0
4 years ago
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What is the slope of a line parallel to y=2x+3?
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Answer:

2

Step-by-step explanation:

2 is the slope of y=2x+3 and any line parralel would have the same slope. therefore the parallel slope would be 2

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3 years ago
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Which of the following is a solution to 2cos2x − cos x − 1 = 0?
Pavel [41]

Answer:

Option A is correct.

Solution for the given equation is, x = 0^{\circ}

Step-by-step explanation:

Given that : 2\cos^2x -\cos x -1 =0

Let \cos x =y

then our equation become;

2y^2-y-1= 0           .....[1]

A quadratic equation is of the form:

ax^2+bx+c =0.....[2] where a, b and c are coefficient and the solution is given by;

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;

y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}

Simplify:

y = \frac{ 1 \pm \sqrt{1+8}}{4}

or

y = \frac{ 1 \pm \sqrt{9}}{4}

y = \frac{ 1 \pm 3}{4}

or

y = \frac{1+3}{4} and y = \frac{1 -3}{4}

Simplify:

y = 1 and y = -\frac{1}{2}

Substitute y = cos x we have;

\cos x = 1

⇒x = 0^{\circ}

and

\cos x = -\frac{1}{2}

⇒ x = 120^{\circ} \text{and} x = 240^{\circ}

The solution set:  \{0^{\circ}, 120^{\circ} , 240^{\circ}\}

Therefore, the solution for the given equation  2\cos^2x -\cos x -1 =0 is, 0^{\circ}





8 0
4 years ago
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