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Len [333]
3 years ago
10

Please help me solve this question. Will make you the

Mathematics
1 answer:
zmey [24]3 years ago
6 0

The relation you have shown is not a function.

In order to be a function, a relation's domain must be continuous in that no x-value is not repeated in any of the points. Since the first two points of the relation are (5,1) and (5,3), you can see that they have the same x-value, meaning that this is not a function.

One quick way you could test this is to quickly sketch a graph and use the vertical line test to see if the relation in question is a function. If it cross the vertical line once in all places, it is a function - if it crosses the vertical line more than once in any place, it is not a function.

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Amayo943,

Remember that with exponents you have to multiply the number of exponets by the same number it's in for example: 1^2 = 1 \times 1 In this case you need to know that:

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