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Len [333]
3 years ago
10

Please help me solve this question. Will make you the

Mathematics
1 answer:
zmey [24]3 years ago
6 0

The relation you have shown is not a function.

In order to be a function, a relation's domain must be continuous in that no x-value is not repeated in any of the points. Since the first two points of the relation are (5,1) and (5,3), you can see that they have the same x-value, meaning that this is not a function.

One quick way you could test this is to quickly sketch a graph and use the vertical line test to see if the relation in question is a function. If it cross the vertical line once in all places, it is a function - if it crosses the vertical line more than once in any place, it is not a function.

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3. Which ordered pair is a solution of the equation y = x – 2? (1 point) (3, 1) (1, 3) (–1, 3) (3, –1)
kozerog [31]
The answer is (3,1)
7 0
3 years ago
Find the 12th term of the arithmetic sequence 2x + 8,6x + 5, 10x + 2, ...
lawyer [7]

Answer: The 12th term is 46x -25

Step-by-step explanation:

It is increasing by 4x and decreasing by 3 through each term, this represents the d. a1 has already been identified as 2x +8, so you just have to write down the formula and the solve form there by plugging in the 12 in (n-1) to find the answer.

8 0
2 years ago
Required
snow_lady [41]

Answer:

19

Step-by-step explanation:

70 - 51 = 19

To check:

19 + 51 = 70

5 0
2 years ago
In the diagram shown , find the size of angle x​
almond37 [142]

Answer:

x = 110°

Step-by-step explanation:

The sum of the interior angles of a polygon is

sum = 180° (n - 2) ← n is the number of sides

Here n = 6, thus

sum = 180° × 4 = 720°

Sum the given angles and equate to 720

125 + x + 130 + 90 + 165 + 100 = 720, that is

610 + x = 720 ( subtract 610 from both sides )

x = 110°

6 0
3 years ago
Maria, Bill, and Eric have a total of $95 in their wallets. Maria has 10 less than Bill. Eric has 3 times what Bill has. How muc
BaLLatris [955]

Answer:

\boxed{Maria \: got \:  \$11} \\  \boxed{Bill \: has \:  \$21}  \\ \boxed{ Eric  \: has \: \$63}

Step-by-step explanation:

let \: maria \: be \to \: m \\ let \: eric \: be \to \: e  \\let \: bill \: be \to \: b  \\then : m =b - 10 \: and \: e =  3b \\ but : m + b + e = 95 \\ hence \to \: (b - 10) + b + (3b) = 95 \\ 2b - 10 + 3b = 95 \\ 5b = 95 + 10 \\ 5b = 105 \\  \boxed{b = 21} \\ m = b - 10 = 21 - 10 \\ \boxed{ m = 11} \\ e = 3b = 3(21)  \\  \boxed{e= 63}

♨Rage♨

5 0
3 years ago
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